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3 years ago

Is y=x squared a linear or nonlinear function

Mathematics

1 answer:

Leto [7]3 years ago

5 0

Answer:

Linear. y = x also equals y = 1x, and you can put a line on a graph using this equation, hence the name linear.

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M is directly proportional to r3 When r = 4, M = 160 a) Work out the value of M when r = 2.

Natali [406]

Answer:

M = 20

Step-by-step explanation:

Given that M is directly proportional to r³ then the equation relating them is

M = kr³ ← k is the constant of proportion

To find k use the condition when r = 4, M = 160, that is

160 = k × 4³ = 64k (divide both sides by 64 )

2.5 = k

M = 2.5r³ ← equation of proportion

When r = 2, then

M = 2.5 × 2³ = 2.5 × 8 = 20

6 0

3 years ago

Read 2 more answers

I need help with this geometry pleaseee

olya-2409 [2.1K]

Answer:

GO STUDY!

Step-by-step explanation:

Good Luck!

7 0

4 years ago

Read 2 more answers

In a class there are 40 students 30 are boys and what is the percentage of girls ....

Artyom0805 [142]

Answer:

25%

Step-by-step explanation:

Total= 40 students

boys +girls= 40

30 +girls= 40

number of girls

= 40 -30

= 10

Percentage of girls

$= \frac{10}{40} \times 100\% \\ = 25\%$

Alternatively,

percentage of girls

= 100% -(percentage of boys)

$= 100\% - ( \frac{30}{40} \times 100\%) \\ = 100\% - 75\% \\ = 25\%$

6 0

3 years ago

Find the length x to the nearest whole number. A right triangle has a vertical leg of length x units, a base leg with a length o

wel

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is $x = 274 \ unites$

Step-by-step explanation:

From the question we are told that

The length of the vertical length is $x$

The length of the base leg is L = 330 + d units

The length of the bisecting line segment is h

The base angle is $\theta = 28^o$

The angle between d and line segment is $\theta_1 = 56^o$

For the first angle

$Tan \theta_1 = \frac{x}{d}$

=> $d = \frac{x}{Tan \theta _1}$

For the whole big triangle

$Tan \theta = \frac{x}{330 + d}$

=> $d = \frac{x}{Tan \theta } -330$

So equating the both d

$\frac{x}{Tan \theta _1} = \frac{x}{Tan \theta } -330$

Substitute values

$\frac{x}{Tan (56)} = \frac{x}{Tan (28) } -330$

$0.6745 x = 1.880x -330$

$1.20549 x = 330$

$x = 274 \ unites$

5 0

3 years ago

M(x)=1/x f(x)=2x-10 find the domain restriction of m(R(x))

AlexFokin [52]

Answer:

x ≠ 5

Step-by-step explanation:

Given

m(x) = 1/x
f(x) = 2x - 10

Composite function

m(f(x)) = 1/ (2x - 10)

The denominator can't be zero

2x - 10 ≠ 0
2x ≠ 10
x ≠ 5

5 0

3 years ago