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Paladinen [302]
2 years ago
5

Plz help it due today and i will give brainliest.

Mathematics
2 answers:
tiny-mole [99]2 years ago
8 0
It is B. You divide 10 by 25 and multiply it by 100
Korolek [52]2 years ago
6 0

Answer:

It would be B. 40%

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I need help plz answer before Monday 26th
IRISSAK [1]
The first one is 3 8/10 are not rotten because 5 3/10- 1 5/10 = 3 8/10

The second one needs information on the strawberries which it dosen't show on the picture.

Hope this helped a bit.
7 0
3 years ago
I suck at this stuff can someone help me out? thank you!
avanturin [10]
A) h=9.9
if that's not correct, i've done these before, i don't know why it wouldn't work?
3 0
3 years ago
Single quadrant ordered pairs
Marianna [84]

Answer:

this four sections are called the quadrants

3 0
3 years ago
) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp
Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

<em>Let </em>\bar X<em> = sample average salary</em>

The z-score probability distribution for sample mean is given by;

                 Z = \frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = mean salary = $1.5 million

            \sigma = standard deviation = $0.9 million

             n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P(\bar X > $1.1 million)

    P(\bar X > $1.1 million) = P( \frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} } >  \frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} } ) = P(Z > -8.89) = P(Z < 8.89)

<em>Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.</em>

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0
3 years ago
In Hillsboro's wig shop, 1/2 of the wigs are blonde and 1/12 of the wigs are brunette. What fraction of the wigs are either blon
ella [17]

Answer:

7/12

Step-by-step explanation:

So, the probability of picking up a blonde wig = 1/2

The probabiliy of picking up a brunette wig = 1/12

The question asks to find th eprobability of picking up either of these types of wigs =

1/2 + 1/12

= 6/12 + 1/12 ( LCM of 12 and 1 is 12 )

= 7/12

Hope this helps

3 0
3 years ago
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