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Serjik [45]
3 years ago
11

ANSWER CORRECTLY ASAP

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0

<em>ANSWER CORRECTLY ASAP </em>

<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)</em>

<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)</em>

<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)3. A tank of compressed gas has a maximum safe pressure limit of 826 kPa. The pressure gauge reads 388 kPa when the temperature is 24.1oC. What is the highest temperature the tank can withstand safely? (632 K)</em>

<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)3. A tank of compressed gas has a maximum safe pressure limit of 826 kPa. The pressure gauge reads 388 kPa when the temperature is 24.1oC. What is the highest temperature the tank can withstand safely? (632 K)4. A gas occupies a volume of 560 cm3 at a temperature of 120.0oC. To what temperature must the gas be lowered, if it is to occupy 400.0 cm3? Assume a constant pressure.</em>

<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)3. A tank of compressed gas has a maximum safe pressure limit of 826 kPa. The pressure gauge reads 388 kPa when the temperature is 24.1oC. What is the highest temperature the tank can withstand safely? (632 K)4. A gas occupies a volume of 560 cm3 at a temperature of 120.0oC. To what temperature must the gas be lowered, if it is to occupy 400.0 cm3? Assume a constant pressure.5. If 122 mL of oxygen are collected at 27.5oC and 740 mmHg, what will the volume be of the dry gas at STP? (760 mmHg = 101.3 kPa)</em>

<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)3. A tank of compressed gas has a maximum safe pressure limit of 826 kPa. The pressure gauge reads 388 kPa when the temperature is 24.1oC. What is the highest temperature the tank can withstand safely? (632 K)4. A gas occupies a volume of 560 cm3 at a temperature of 120.0oC. To what temperature must the gas be lowered, if it is to occupy 400.0 cm3? Assume a constant pressure.5. If 122 mL of oxygen are collected at 27.5oC and 740 mmHg, what will the volume be of the dry gas at STP? (760 mmHg = 101.3 kPa)6. A sample of neon gas has a volume of 0.261 L and a pressure of 108.5 kPa. What volume will the gas occupy at 96.5 kPa, if the temperature remains constant?</em>

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sammy [17]

9514 1404 393

Answer:

  1a. E = 5×1.59^t

  1b. 32 GWh

  1c. 1986

Step-by-step explanation:

1a. An exponential model looks like

  f(t) = a·b^t

where 'a' is the value when t=0, and 'b' is the growth factor in the time period associated with t.

Here, 'a' is 5 (GWh), and 'b' is 1+59% = 1.59. Then the desired model is ...

  E = 5·1.59^t . . . . . where t is years after 1980, and E is in GWh.

__

1b. For t=4, we have ...

  E = 5·1.59^4 ≈ 31.96 ≈ 32

About 32 GWh was generated in 1984.

__

1c. The value of t for a given value of E is ...

  E/5 = 1.59^t . . . . divide by 5

  log(E/5) = t·log(1.59) . . . . take logarithms

  t = log(E/5)/log(1.59) . . . . divide by the coefficient of t

For E = 80, the years after 1980 are ...

  t = log(80/5)/log(1.59) ≈ 5.98

About 80 GWh were generated in 1986.

4 0
3 years ago
H(x)=(x+5)^2 if we solve h(x)=36
Ivan

Answer:

x =  - 11

Step-by-step explanation:

Solving

(x + 5)² = 36 ( take square root of both sides )

x + 5 = ± \sqrt{36} = ± 6 ( subtract 5 from both sides )

x = - 5 ± 6

Then

x = - 5 + 6 = 1

x = - 5 - 6 = - 11

The other solution is x = - 11

6 0
3 years ago
March 21, the 80th day of the year, is the spring equinox. find the number of hours of daylight in fairbanks on this day
pentagon [3]
According to a daylight calculator for Fairbanks, AK, sun rises at 07:40 and sun sets at 20:12, giving 12 hours and 32 minutes of daylight.

Note that it is not a mistake that daylight is not exactly 12 hours on that day due to refraction of the sun's rays at sunrise and sunset.

At Fairbanks, near equality to 12 hours occurs on March 16 with sunrise at 07:58 and sunset at 19:57.
3 0
3 years ago
Hii please help i’ll give brainliest if you give a correct answer!
Vika [28.1K]

Answer:

8 and 1/4 cups sugar is your answer. In 5 and 1/3 cups is 8 and 1/4 cups sugar.

Step-by-step explanation:

Brainly please hope this is correct please tell me if I wrong.

5 0
3 years ago
Solve: 2a - b = ac + 3b for a
Greeley [361]

Answer:

a/ac + 2b

Step-by-step explanation:

2a - b = ac + 3b

2a = ac +4b

2a/ac+4b = a/ac + 2b

8 0
3 years ago
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