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The distance between the tree and the tower is 30√3m.
Justification:
<u>Let the situation be in a right angleABC form as shown in attached figure</u>.
<u>Given the height of the tower is 30m and the angle of depression to the base of the tree measure 30°</u>.
So, In ΔABC
tanθ = p/b
tan30° = 30/BC
1/√3 = 30/BC
BC = 30√3m.
