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2 years ago

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Which word describes 3y in the given expression? a) coefficient b)constant c) factor d) term I need answers quick

1 answer:

otez555 [7]2 years ago

4 0

Constant duuuuuuuuuuuuu

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Please answer the question now in two minutes

oksian1 [2.3K]

Answer:

Coordinates of point P is $(-14,3)$ .

Step-by-step explanation:

Given that mid point of line segment $\overline {PQ}$ is at <em>M(-9, 8.5).</em>

Q is at <em>(-4, 14)</em>.

Let coordinate of P be $(x,y)$ .

Using the ratio, we can say the following:

<em>The coordinates of mid point</em> $(X,Y)$ of a line with endpoints $(x_1, y_1)$ and $(x_2, y_2)$ is given as:

$X=\dfrac{(x_1+ x_2)}{2}$

$Y=\dfrac{(y_1+ y_2)}{2}$

Using the formula for above given dimensions:

$-9 =\dfrac{x+(-4)}{2}\\\Rightarrow x = -18+4 = -14$

$8.5=\dfrac{(14+ y)}{2}\\\Rightarrow y = 17-14 =3$

So, the <em>coordinates of point P are</em> $(-14,3)$ .

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Brrunno [24]

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pllllllls I need help right triangle and trigonometry special right triangles find the value of each variable

yanalaym [24]

$\huge {\mathfrak{Answer : }}$

we know,

$\boxed{\cos( \theta) = \dfrac{base}{hypotenuse}}$

so,

$\cos(30) = \dfrac{24}{x}$

$\dfrac{ \sqrt{3} }{2} = \dfrac{24}{x}$

$x = \dfrac{24 \times 2}{ \sqrt{3} }$

$x = 8 \sqrt{3} \times 2$

$x = 16 \sqrt{3}$

now,

$\boxed{ \tan( \theta) = \frac{perpendcular}{base} }$

$\tan(30) = \dfrac{y}{24}$

$\dfrac{1}{ \sqrt{3} } = \dfrac{y}{24}$

$y = \dfrac{24}{ \sqrt{3} }$

$y = 8 \sqrt{3}$

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3 years ago

Simplify (3v^3)^2/15v^7

leonid [27]

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2 years ago

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