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gizmo_the_mogwai [7]
3 years ago
9

What is the area of the figure

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0
...whars the figure??? You did give us dimensions but not the figure..
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Geometry PEOPLE HELP
White raven [17]

Answer: second option.

Step-by-step explanation:

Given the transformation T:(x,y)→(x-5,y+3)

 You must substitute the x-coordinate of the point A (which is x=2) and the y-coordinate of the point A (which is y=-1) into (x-5,y+3) to find the x-coordinate and the y-coordinate of the image of the point A.

Therefore, you get that the image of A(2,-1) is the following:

(x-5,y+3)=(2-5,-1+3)=(-3,2)

You can observe that this matches with the second option.

6 0
3 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
3 years ago
What is the formula for the area of a triangle?
SashulF [63]

<em>The</em><em> </em><em>formula</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>area</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>triangle</em><em> </em><em>is</em><em> </em><em>:</em>

<em>1</em><em>/</em><em>2</em><em> </em><em>base</em><em>*</em><em>height</em>

<em>For</em><em> </em><em>inst</em><em>ance</em><em>:</em>

<em>base</em><em>=</em><em>4</em><em> </em><em>cm</em>

<em>height</em><em>=</em><em>5</em><em>c</em><em>m</em>

<em>area</em><em> </em><em>of</em><em> </em><em>traingle</em><em>=</em><em>1</em><em>/</em><em>2</em><em>*</em><em>b</em><em>*</em><em>h</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>/</em><em>2</em><em>*</em><em>4</em><em>*</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>0</em><em>c</em><em>m</em><em>^</em><em>2</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

6 0
3 years ago
If the acute angles in a right triangle are in the ratio of 5:4 find the measure of the smallest angle
deff fn [24]
Let's create this right triangle.  We will call it triangle ABC with angle B as the right angle, angle A being the larger of the angles A and C.  If the ratio is 5:4, then it is A:C.  5+4 = 9.  The measure of the right angle, angle ABC = 90, and 90 divided by 9 is 10.  So angle A is 5 * 10 which is 50 degrees, and angle C is 4 * 10 which is 40 degrees.  The smallest angle, angle C, is 40 degrees.
6 0
3 years ago
A cyclist bikes at a constant speed for 22 miles. He then returns home at the same speed but takes a different route. His return
brilliants [131]
How concerned are you with how to get the answer?
Because I know the answer is 5 miles per hour
22/5= 4.4 hours
27/5= 5.4 hours

Alright this is how you solve it
Distance over time equals speed
So 22/y=x and 27/y+1=x
Start by solving for time by having these two equations equal each other
22/y=27/y+1
Cross multiply to get
22(y+1)=27y
22y+22=27y
Isolate Y
5y=22
Y=4.4
Now solve for X which is the speed, you can plug in Y to either of the two equations
22/4.4=x
X=5 miles per hour
4 0
3 years ago
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