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garri49 [273]
3 years ago
14

Help Me Plz!!!!!!!!!!!!!

Mathematics
1 answer:
Strike441 [17]3 years ago
8 0

Answer:

a = 6\sqrt 3,\:\:b =12,\:\:c=6\sqrt 2

Step-by-step explanation:

by \: 30 \degree - 60 \degree - 90 \degree \: theorem \\  \\ 6 =  \frac{1}{2} b\\  \\ 6 \times 2 = b \\  \\ 12 = b \\  \\ \huge\red {\boxed {b= 12}} \\  \\ a =  \frac{ \sqrt{3} }{2} b \\  \\ a =  \frac{ \sqrt{3} }{2}  \times 12 \\  \\ \huge\purple {\boxed {a = 6 \sqrt{3}}} \\  \\ c =  \frac{1}{ \sqrt{2} } b \\  \\ c =  \frac{1}{ \sqrt{2} }  \times 12 \\  \\ c =  \frac{ \sqrt{2} }{2}  \times 12 \\  \\ \huge\orange {\boxed {c = 6 \sqrt{2}}} \\  \\

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