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mr_godi [17]
3 years ago
6

Sac had a rope that was 15 feet long. He cut it into three pieces. The first piece was 3.57 feet longer than the second piece. T

he third piece was 2.97 feet longer than the second piece. How long was the third piece of rope?
Mathematics
1 answer:
harina [27]3 years ago
7 0

Answer:

5.79 feet

Step-by-step explanation:

Let us represent

First piece = x

Second piece = y

Third piece = z

Sac had a rope that was 15 feet long.

x + y + z = 15

He cut it into three pieces.

The first piece was 3.57 feet longer than the second piece.

x = 3.57 + y

The third piece was 2.97 feet longer than the second piece.

z = 2.97 + y

How long was the third piece of rope?

x + y + z = 15

3.57 + y + y + 2.97 + y = 15

3y + 6.54 = 15

3y = 15 - 6.54

3y = 8.46

y = 8.46/3

y = 2.82 feet

Therefore, the length of the third piece z = 2.97 + y

z = 2.82 + 2.97

z = 5.79 feet

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