U should subtract the first number and the second one together and see what you get
1 to the ninth power can be represented by
1•1•1•1•1•1•1•1•1
1 times any number or put to any power will always be one.
Hope this helped.
Step-by-step explanation:
If X is a finite Hausdorff space then every two points of X can be separated by open neighborhoods. Say the points of X are 
. So there are disjoint open neighborhoods 
and 
, of 
and 
respectively (that's the definition of Hausdorff space). There are also open disjoint neighborhoods 
and 
of and 
respectively, and disjoint open neighborhoods 
and 
of and 
, and so on, all the way to disjoint open neighborhoods 
, and 
of and 
respectively. So 
has every element of 
in it, except for . Since 
is union of open sets, it is open, and so 
, which is the singleton 
, is closed. Therefore every singleton is closed.
Now, remember finite union of closed sets is closed, so 
is closed, and so its complemented, which is is open. Therefore every singleton is also open.
That means any two points of belong to different connected components (since we can express X as the union of the open sets 
, so that is in a different connected component than 
, and same could be done with any 
), and so each point is in its own connected component. And so the space is totally disconnected.
312 people bought balcony seats and 396 people bought ground seats.
