They have a period so the decimals
Answer:
Let us first jot down all the data given in the question;
Number of low quality computers (LQ) = 72
Number of medium quality computers (MQ) = 112
Number of high quality computers (HQ) = 711
∴ Total number of computers found in a random sample = 72 + 112 + 711 = 895.
∴ To find the probability of purchase for each category of computers, we use the following formula;
So,
P(LQ) = 72/895 = 0.08
P(MQ) = 112/895 = 0.125
P(HQ) = 711/895 = 0.794
Ans) Probability of purchase of a low quality computer, a medium quality computer, and a high quality computer are 0.08, 0.125, and 0.794 respectively
A similar answer can be found here:-
https://www.brainly.com/question/7297949
Answer:
x = 5.5
Step-by-step explanation:
PM = MR
4x - 12 = -2x + 21 {add 2x to both the sides}
4x - 12 + 2x = -2x + 2x + 21
6x - 12 = 21 {Add 12 to both sides}
6x - 12 + 12 = 21 + 12
6x = 33
x = 33/6
x = 5.5
Answer:
12
Step-by-step explanation: