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kherson [118]
2 years ago
7

Jade graphed a system of linear equations. The two lines are right on top of each other, so it appears to be only one line. Whic

h statement about the number of points that satisfy the system is true?
Mathematics
1 answer:
kap26 [50]2 years ago
4 0

Answer:

Are we supposed to look at a picture of the graph bec if we are I don’t see it

Step-by-step explanation:

You might be interested in
Please Help me Please Please the question and options are in the picture
Vladimir [108]

The correct answer is B)x = \frac{y - p + mq}{m}.

In order to find this, we need for follow the order of operations.

y - p = m(x - q) ----> Divide both sides by m

\frac{y - p}{m} = x - q ----> add q to both sides

\frac{y - p}{m} + q = x ---> now we need to give it a common denominator. Multiply the q term by m/m

\frac{y - p + mq}{m} = x

This is our final answer.

5 0
3 years ago
Taron unpacked 47 boxes of light bulbs for the discount warehouse. Each box contained 6 bulbs. How many bulbs were in the 47 box
Zolol [24]

Answer:

282 bulbs

Step-by-step explanation:

Find how many bulbs there were by multiplying 47 by 6

47(6)

= 282

So, in the 47 boxes, there were 282 bulbs

7 0
3 years ago
A manager wants to build​ 3-sigma ​x-bar control limits for a process. The target value for the mean of the process is 10​ units
murzikaleks [220]

Answer:

io

Step-by-step explanation:

8 0
3 years ago
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
3 years ago
Law of Sine.
kykrilka [37]

Answer:

Bc=20

Step-by-step explanation:

Sin61=BC/AC=BC/23

BC=23sin61=20

4 0
3 years ago
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