Sqrt(1-3x)=x+3
[sqrt(1-3x)]^2=(x+3)^2
1-3x=(x+3)(x+3)
1-3x=x^2+6x+9
-3x=x^2+6x+8
0=x^2+9x+8
The answers are -1 and -8 BUT, we have to plug them back into the original equation to make sure we don't get a negative under the square root sign.
After doing this, we realize that only -1 works, so the answer is x=-1
Sorry that this took forever to answer. I was thinking of a good way to explain this, and if you need any further explanation, message me:)
Best wishes:)
For number 3 add all the numbers and divide how numbers you have
Answer:
times each other
Step-by-step explanation:
times by each other
Answer:
ohh hiii and I dob5 understand that -
Hey there!
To solve, let's first add 5 to both sides.
xy=k+5
Now we divide both sides by y.
x=
I hope this helps!
