Alternate exterior angles because the are OUTSIDE of the parallel lines
Answer:
BC < ED ⇒ answer A
Step-by-step explanation:
* Lets revise some facts in the triangle
- If one side of a triangle is longer than another side, then the angle
opposite the longer side will be larger than the angle opposite the
shorter side
- If one angle in a triangle is larger than another angle in a triangle,
then the side opposite the larger angle will be longer than the side
opposite the smaller angle
* Lets solve the problem
- In the two triangles BCD and DEB
∵ CD = 8 and BE = 8
∴ CD = BE
∵ Side BD is a common side in the two triangles
- The third side in Δ BCD is BC and the third side in DEB is DE
∵ BC is the opposite side to the angle of measure 24°
∵ ED is the opposite side to the angle of measure 30°
∵ The measure 24° < the measure 30°
∴ The side opposite to the angle of measure 24° < the side opposite
to the angle of measure 30°
∵ The other two sides of the 2 triangles BCD and DEB are equal
∴ We can compare between the 3rd sides in the Δ BCD and Δ DEB
∴ BC < ED
Guessing that the 3 was suppose to be an exponent.
The answer written in standard form is :
4x^3 + 10x - 4
This is called a cubic trinomial.
Answer:
Option H, π/3 and 2π/3
Step-by-step explanation:
sin x = sqrt(3) / 2
<em>It happens at 60 degrees and 120 degrees. In radians, it is π/3 and 2π/3</em>
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Answer: Option H, π/3 and 2π/3
