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lyudmila [28]
3 years ago
9

How do I find the distance between (3,4) and (5,4)​

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

2

Step-by-step explanation:

the y values are the same so you just have to subtract the biggest x value from the smallest x value

5-3=2

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Meg lives in Indianapolis and wants to visit her mom in Lima. She has been meaning to go to a chiropractor in Dayton, so she is
Anna11 [10]
First she would drive 165 miles.
Now we minus the distance of both cities. 173-165=
8 more miles.
7 0
4 years ago
What is the value of the expression when n = 3?<br> GO<br> - 2 n(5 + n-8-3n)
lukranit [14]

Answer:

54

Step-by-step explanation:

since n = 3

= -2n ( 5n+n-8-3n)

= -2 (3) ( 5+(3)-8-3(3) )

= -6 (5+3-8-9)

= -6 (5-5-9)

= -6 (-9)

= 54.

8 0
3 years ago
A line’s equation is given in point-slope form:<br> y−6=(−23)(x+6)<br> This line’s slope is?
Nikolay [14]

The slope of the line is -23

<h3>How to determine the slope of the line?</h3>

The line’s equation is given in point-slope form:

y − 6 = (−23)(x + 6)

The line’s equation in point-slope is represented as:

y − y1 = m(x - x1)

Where

m represents the slope

By comparing y − y1 = m(x - x1) and y − 6 = (−23)(x + 6), we have

m = -23

Hence. the slope of the line is -23

Read more about slope at:

brainly.com/question/3493733

#SPJ1

6 0
2 years ago
Please Show Work 6x(-4) Six times negative four.
Ainat [17]

Answer:

6 x (-4)

= (-24)

Step-by-step explanation:

when multiplying integers, you first need to multiply the numbers. Then you need to look at the signs if both numbers have the same signs or if it doesn't. if the signs are the same, the product is a positive . If the two numbers have different signs, you will get a negative product.

NOTE: if a number doesn't have a sign, it's a positive number

7 0
3 years ago
Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

  • \theta = 240°
  • r = 16 ft

\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 14 cm

\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

  • \theta=\dfrac{ \pi}{2}
  • r = 10 mi

\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

  • \theta = 60°
  • r = 7 km

\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
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