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garri49 [273]
3 years ago
15

Parent function of h(x)=|x+5|-2

Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

g(x)=|x|

Step-by-step explanation:

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I desperately need help.
erik [133]

Answer:

first solve for x

8x=20

x=2.5

5x=17

x=3.4

then your equations

Madison: y=2.5x

Lucas: y=3.4x

then your ordered pairs

Madison: (4,10)

Lucas:(3,10.2)

then your slope

Madison-2.5

Lucas-3.4

I hope this is good enough:

8 0
3 years ago
Help plsplspls ?????
choli [55]

Answer:

It looks like it could be D.

Step-by-step explanation:

5 0
3 years ago
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Use the expression to complete the statements. (0.5)10 (0.5)10 is the . (0.5) is the of (0.5)10. 10 is the of (0.5)10. A power i
RideAnS [48]

Question:

Use the expression to complete the statements.

(0.5)^{10\\

________ is the  power .

(0.5) is the  ________

A ______ is another way to write

Answer:

0.5 is the base

10 is the power

(0.5)^{10\\ = (\frac{1}{2})^{10} -- another way to write

Step-by-step explanation:

Given

(0.5)^{10\\

Required

Fill ion the gaps

(0.5)^{10\\ is pronounced as; 0.5 raise to the power of 10

From the above statement, we can deduce the following:

0.5 is the base

10 is the power

Lastly, another way to write (0.5)^{10\\

Express 0.5 as a fraction

(\frac{5}{10})^{10}

Simplify the fraction

(\frac{5/5}{10/5})^{10}

(\frac{1}{2})^{10}

Hence:

(0.5)^{10\\ = (\frac{1}{2})^{10}

3 0
3 years ago
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Because 9 is a solution of x> 5
notka56 [123]

Answer:

Wiat what can you explain?

7 0
3 years ago
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Find the work (in ft-lb) required to pump all the water out of a cylinder that has a circular base of radius 7 ft and height 200
Virty [35]

Answer:

<em>work done is equal to 384279168 lb-ft</em>

<em></em>

Step-by-step explanation:

The cylinder has a circular base of 7 ft.

The height of the cylinder is 200 ft

The weight density of water in the cylinder is 62.4 lb/ft^3

First, we find the volume of the water in the cylinder by finding the volume of this cylinder occupied by the water.

The volume of a cylinder is given as \pi r^{2} h

where, r is the radius,

and h is the height of the cylinder.

the volume of the cylinder = 3.142* 7^{2}*200 = <em>30791.6 ft^3</em>

Since the weight density of water is 62.4 lb/ft^3, then, the weight of the water within the cylinder will be...

weight of water = 62.4 x 30791.6 = <em>1921395.84 lb</em>

We know that the whole weight of the water will have to be pumped out over the height of cylindrical container. Also, we know that the work that will be done in moving this weight of water over this height will be the product of the weight of water, and the height over which it is pumped. Therefore...

The work done in pumping the water out of the container will be

==> (weight of water) x (height of cylinder) = 1921395.84 x 200

==> <em>work done is equal to 384279168 lb-ft</em>

7 0
4 years ago
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