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Debora [2.8K]
3 years ago
8

I NEED HELP RIGHT NOW

Mathematics
2 answers:
Allisa [31]3 years ago
6 0

Oof the answer is you (and by you I mean B)

Grace [21]3 years ago
6 0
The answer will be... B
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In isosceles $\triangle abc$ (with $ab = ac$), point $d$ lies on $ab$ such that $cd = cb$. if $\angle adc = 115^\circ$, what is
Nuetrik [128]

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Answer: 15°.

3 0
3 years ago
Read 2 more answers
Find the volume of Prism A
Brilliant_brown [7]

Answer:

25....

Step-by-step explanation:

l *b*h....formula is applied

4 0
3 years ago
Read 2 more answers
a recipe requires 2.5 teaspoons of sugar to make a candy bar. which equation shows the number of teaspoons of sugar, y, needed t
padilas [110]
If you would like to know the equation that shows the number of teaspoons of sugar needed to make x candy bars, you can calculate this using the following steps:

2.5 teaspoons of sugar ... 1 candy bar
y teaspoons of sugar = ? ... x candy bars = ?

2.5 * x = 1 * y
2.5 * x = y
y = 2.5 * x

The correct result would be <span>y = 2.5 * x.</span>
5 0
3 years ago
A radio antenna is kept perpendicular to the ground by three wires of equal length. The wires touch the ground at three points o
Elena-2011 [213]

Answer:

The coordinates of the base of the antenna is (-6. 1)

Step-by-step explanation:

Here  we are required to find the center of a circle given points on the circumference

The equation of  a circle is

(x - h)² + (y - k)² = r²

Where:

x and y are points on the circumference

h and k are coordinates of the center of the circle and

r = The radius of the circle

Since we have the values for the points on the circumference, we are left with three unknowns, which we can find with three equations as follows;

By plugging in the values for x and y at the respective points we get,

At (9, -19) → (9 - h)² + (-19 - k)² = r²...............(1)

At (-21, -19) → (-21 - h)² + (-19 - k)² = r².....,...(2)

At (14, 16 ) → (14 - h)² + (16 - k)² = r² ............(3)

Solving, we get  from (1)  (-19 - k)² = r² - (9 - h)²

Plugging in the value of (-19 - k)² in equation (2) we get

(-21 - h)² + r² - (9 - h)² = r²

So that (-21 - h)²  - (9 - h)² = r² -  r² = 0

and   (-21 - h)²  - (9 - h)² = 0 gives

60·h +360 = 0 or h = -6

Plugging in the value of h = -6 in equation (3) we get

(14 - (-6))² + (16 - k)² = r²

20² + (16 - k)² = r² .................(4)

similarly from equation (1) we get

(9 - (-6))² + (-19 - k)² = r²

15² + (-19 - k)² = r²  ................(5)

Subtracting equation (5) from (4) gives

20² - 15² +  (16 - k)² - (-19 - k)² = 0

Which gives

-70·k + 70 = 0

or k = 1

Therefore the coordinates of the base of the antenna = (-6. 1).

6 0
3 years ago
Find the lateral surface area of the cylinder. Round to the nearest tenth if necessary.
son4ous [18]

Answer:

613.24

Step-by-step explanation:

hope this helps, let me know if you get it right

8 0
3 years ago
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