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3 years ago

2+3-6+0*4+1+2+3..........

Mathematics

2 answers:

Nutka1998 [239]3 years ago

4 0

Answer:

the ans is 6 it was a easy one

shepuryov [24]3 years ago

3 0

-10
Explanation: (2+3-6+0= -1)(4+1+2+3=10)
-1x10= -10

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amy places adopt on a coordinate plane at (-3,-6) she wants to place another dot across the y-axis and it must be 8 points away.

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3 years ago

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Winnie wrote the following riddle.I am a number between 60 and 100.My ones digit is two less than my tens digit.I am a prime num

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Answer:

Step-by-step explanation:

60<xy<100

y -2 =x

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3 years ago

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3 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

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3 years ago

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3 years ago

2+3-6+0*4+1+2+3..........​

2+3-6+0*4+1+2+3..........