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mariarad [96]
3 years ago
7

Use trigonometric ratios to solve the right triangle.

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0

Answer:

DF=15, DE=5\sqrt{3}

Step-by-step explanation:

sin(60)=\frac{DF}{EF} =\frac{DF}{10\sqrt{3} }\\DF=10\sqrt{3} sin(60)=10\sqrt{3} \times \frac{\sqrt{3} }{2} =15\\cos(60)=\frac{DE}{EF} =\frac{DE}{10\sqrt{3} }\\DE=10\sqrt{3} cos(60)=10\sqrt{3} \times \frac{1 }{2} =5\sqrt{3}

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