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Alex777 [14]
3 years ago
5

How do you solve this Matrix equation x+2x-3z=-2 x-y+z=-1 3x+4y-4z= 4

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer:

look this up and watch this video

Step-by-step explanation:

The solution of `2x + y + z = 1 , x-2y-3z = 1 , 3x +2y +4z=5` is 1)1,2,3 2) 1,2,-3 3) 1.-3.2 4)...

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(07.01, 07.02 LC) Factor the greatest common factor: −5k2 + 20k − 30.
Goshia [24]

Answer:

-5(k2-4k+6)

Step-by-step explanation:

I think is -5(k2-4k+6)

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3 years ago
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There are 48 customers in 4 checkout lanes, how many customers in 1 checkout lane ?
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12 customers on 1 checkout lane.
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A total of 2n cards, of which 2 are aces, are to be randomly divided among two players, with each player receiving n cards. Each
klasskru [66]

Answer:

P(X_s^c|X_F) =0.2

P(X_s^c|X_F) =0.31

P(X_s^c|X_F) =0.331

Step-by-step explanation:

From the given information:

Let represent X_F as the first player getting an ace

Let X_S to be the second player getting an ace and

\sim X_S as the second player not getting an ace.

So;

The probabiility of the second player not getting an ace  and the first player getting an ace can be computed as;

P(\sim X_S| X_F) = 1 - P(X_S|X_F)

P(X_S|X_F) = \dfrac{P(X_SX_F)}{P(X_F)}

Let's determine the probability of getting an ace in the first player

i.e

P(X_F) = 1 - P(X_F^c)

= 1 -\dfrac{(^{2n-2}_n)}{(^{2n}_n)}}

= 1 - \dfrac{n-1}{2(2n-1)}

=  \dfrac{3n-1}{4n-2} --- (1)

To determine the probability of the second player getting an ace and the first player getting an ace.

P(X_sX_F) = \text{ (distribute aces to both ) and (select the left over n-1 cards from 2n-2 cards}P(X_sX_F) = \dfrac{2(^{2n-2}C_{n-1})}{^{2n}C_n}

P(X_sX_F) = \dfrac{n}{2n -1}---(2)

P(X_s|X_F) = \dfrac{2}{1}

P(X_s|X_F) = \dfrac{2n}{3n -1}

Thus, the conditional probability that the second player has no aces, provided that the first player declares affirmative is:

P(X_s^c|X_F) = 1- \dfrac{2n}{3n -1}

P(X_s^c|X_F) = \dfrac{n-1}{3n -1}

Therefore;

for n= 2

P(X_s^c|X_F) = \dfrac{2-1}{3(2) -1}

P(X_s^c|X_F) = \dfrac{1}{6 -1}

P(X_s^c|X_F) = \dfrac{1}{5}

P(X_s^c|X_F) =0.2

for n= 10

P(X_s^c|X_F) = \dfrac{10-1}{3(10) -1}

P(X_s^c|X_F) = \dfrac{9}{30 -1}

P(X_s^c|X_F) = \dfrac{9}{29}

P(X_s^c|X_F) =0.31

for n = 100

P(X_s^c|X_F) = \dfrac{100-1}{3(100) -1}

P(X_s^c|X_F) = \dfrac{99}{300 -1}

P(X_s^c|X_F) = \dfrac{99}{299}

P(X_s^c|X_F) =0.331

8 0
3 years ago
Write the given sentence as an equation.
Leni [432]
D.)T+19=3(t - 7)
hope it helped
8 0
4 years ago
Point Q is the midpoint of AB. Q has coordinates of (-2, 4) and A has coordinates of (4,6). What are the coordinates of point B?
erastovalidia [21]

Step-by-step explanation:

Let (x, y) be the coordinates of point B.

(4, 6) => (-2, 4) => (x, y)

We have 2(-2) = 4 + x and 2(4) = 6 + y.

Solving these, we get x = -8 and y = 2.

Hence the coordinates of point B is (-8, 2).

6 0
3 years ago
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