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NeTakaya
3 years ago
11

PLEASE HELP ME!! write three to the power of two sevenths in radical form and explain?

Mathematics
2 answers:
ruslelena [56]3 years ago
8 0

Answer:

4782969

Step-by-step explanation:

jeka943 years ago
6 0

Answer:

<u></u>\sqrt[7]{3^{2}}<u></u>

Step-by-step explanation:

3^{2/7}

^ That is 3 to the 2/7ths power. We know that. Now it needs to be in radical form. That takes a bit of thinking.

If you have a power that is less than one (like 1/2) it is can be written as a root. So say you're given 2^{1/2}. That is the same exact thing as saying \sqrt{2}. It's the same thing. You can say it either way.

In the same way, a squared power, like 2^{2}, is the same as representing it like a fraction, like 2^{2/1}. They both mean the same thing.

So by pointing these out, a fraction power = the power / the root.

If that makes sense.

So, with this in mind, let's look at what we have again.

3^{2/7}

So we can split it up to say that 3 is raised to a 2nd power times a 1/7th power.

So we know what a 3 to the 2nd power is: 3^{2}.

And since we have a fraction that's also included, we now know that is a root. So we can represent that like this: \sqrt[7]{3}.

But those two answers need to be combined. We can do that like this: \sqrt[7]{3^{2}}

Answer: \sqrt[7]{3^{2}}

So there it is! I hope that helped you!!

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Dmitriy789 [7]

Answer:

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Xochitl bought 5 shirts all for the same price.
mylen [45]

Answer:

Each shirt costed 9 dollars.

Step-by-step explanation:

35+10=45 (initial price)

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3 years ago
Ben frank is an electrician who installs lighting fixtures. He charges (in dollars) his clients 15h + 40f where h is the number
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15h + 40f

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8 0
3 years ago
What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle
STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2

\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4

\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}

=4.2

3 0
3 years ago
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