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GarryVolchara [31]
3 years ago
11

What's six tenths divided by seven ​

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

3/35

Step-by-step explanation:

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#54 Simplify and write the answers using positive exponents only.
kramer
Gg easy

remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)

so
( \frac{6mn^{-2}}{3m^{-1}n^2} )^{-3}=
( \frac{6}{3} )^{-3}( \frac{m}{m^{-1}} )^{-3}( \frac{n^{-2}}{n^2} )^{-3}=
(2^{-3})((m^2)^{-3})((n^{-4})^{-3})=
( \frac{1}{2^3})(m^{-6})(n^{12})=
( \frac{1}{8} )( \frac{1}{m^6})(n^{12})=
\frac{n^{12}}{8m^6}

8 0
3 years ago
30 inches to 3 inches​
kondor19780726 [428]

Answer:

I believe its 3

Step-by-step explanation:

5 0
2 years ago
A bag contains 3 red and 6 white tokens. Tokens are randomly selected and removed one at a time until the bag is empty. Find the
disa [49]

Answer:

Therefore, the probability is P=1/84.

Step-by-step explanation:

We have a  bag contains 3 red and 6 white tokens. Tokens are randomly selected and removed one at a time until the bag is empty.

We conclude that in a bag have 9 tokens.  

We calculate the probability that the red tokens are drawn consecutively.

We calculate the number of possible combinations:

C_3^9=\frac{9!}{3!(9-3)!}=84\\\\

Number of favorable combinations is 1.

Therefore, the probability is P=1/84.

4 0
3 years ago
1. List the domain and range of the relation
Naddik [55]

Answer:

Domain: {(7, 9, 0)}

Range: {(-2, 9, 11, 2)}

3 0
3 years ago
Which expression is equivalent to 12•2•3
Ivahew [28]

Answer:

4 x 3 x 2 x 3

Step-by-step explanation:

4 x 3 = 12

12 x 2 = 24

24 x 3 = 36

It doesn't matter what order it will come out to be 36 in every situation, since PEMDAS isn't needed.

3 0
3 years ago
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