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3 years ago

Please help me please

Mathematics

1 answer:

salantis [7]3 years ago

6 0

Answer:

16x^3-9x^2+4x-4

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Write the eqWrite the equation of the line, in point-slope form. Identify the point (-2, -2) as (x1, y1). Use the box provided o

puteri [66]

Given that the line passes through two points

(-2,-2) and (x1,y1)

Equation in point slope form is

y-y1 = m(x-x1)

substitute for slope

Hence equation of the line = $\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)$

Since we donot know the value of x1or y1 the equation would contain x1, y1 also as answer.

Answer in point slope form is

$\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)$

8 0

3 years ago

A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh

Stella [2.4K]

A parabola is a mirror-symmetrical U-shape.

The equation of the parabola is $\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$
The focus is $\mathbf{Focus = (80, -1760)}$
The directrix is $\mathbf{y = \frac{1}{640}}$
The axis of the symmetry of parabola is: $\mathbf{x = 80}$

From the question, we have:

$\mathbf{Vertex: (h,k) = (80,10)}$

$\mathbf{Origin: (x,y) = (0,0)}$

The equation of a parabola is:

$\mathbf{y = a(x - h)^2 + k}$

Substitute the values of origin and vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{0 = a(0 - 80)^2 + 10}$

$\mathbf{0 = a(- 80)^2 + 10}$

$\mathbf{0 = 6400a + 10}$

Collect like terms

$\mathbf{6400a =- 10}$

Solve for a

$\mathbf{a =- \frac{1}{640}}$

Substitute the values of a and the vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

The focus of a parabola is:

$\mathbf{Focus = (h, \frac{k+1}{4a})}$

Substitute the values of a and the vertex in $\mathbf{Focus = (h, \frac{k+1}{4a})}$

$\mathbf{Focus = (80, \frac{10+1}{4 \times -\frac{1}{640}})}$

$\mathbf{Focus = (80, -\frac{11}{\frac{1}{160}})}$

$\mathbf{Focus = (80, -11\times 160)}$

$\mathbf{Focus = (80, -1760)}$

The equation of the directrix is:

$\mathbf{y = -a}$

So, we have:

$\mathbf{y = \frac{1}{640}}$ ----- the directrix

The axis of symmetry is:

$\mathbf{x = -\frac{b}{2a}}$

We have:

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

Expand

$\mathbf{y = -\frac{1}{640}(x^2 -160x + 6400) +10}$

Expand

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x - 10 +10}$

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x }$

A quadratic function is represented as:

$\mathbf{y = ax^2 + bx + c}$

So, we have:

$\mathbf{a = -\frac{1}{640}}$

$\mathbf{b = \frac{1}{4}}$

Recall that:

$\mathbf{x = -\frac{b}{2a}}$

So, we have:

$\mathbf{x = -\frac{1/4}{2 \times -1/640}}$

$\mathbf{x = \frac{1/4}{1/320}}$

This gives

$\mathbf{x = \frac{320}{4}}$

$\mathbf{x = 80}$

Hence, the axis of the symmetry of parabola is: $\mathbf{x = 80}$

Read more about parabola at:

brainly.com/question/21685473

6 0

3 years ago

What is the answer to 8^6÷8

Oliga [24]

The answer to this equation is 8^5

7 0

2 years ago

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It takes 13 more copies of the angle for the last angle to overlap the first horizontal ray. What is the measure of each angle?

nalin [4]

Missing part in the heading of the question:
For this question, use the diagram shown. The diagram shows the result of constructing a copy of an angle adjacent to one of the rays of the original angles. Assume the pattern continues.

Answer:
measure of each angle = 24°

Explanation:
The diagram shows two angles, if we add 13 more copies, the number of angles would be 15 angles

Now, when the 15 angles are drawn, the last angle would overlap with the first horizontal ray.
This means that the angles form one complete rotation around the point.

This means that the sum of the 15 angles together is 360°.

We know the all 15 angles are equal. Assume that the measure of each is x.
15 x = 360
x = 360 / 15
x = 24°

Hope this helps :)

6 0

3 years ago

If a figure is translated 7 units to the right and 4 units down, what can be said about the perimeter of the transformed image?

andrew-mc [135]

Answer:

4,7

Step-by-step explanation:

8 0

3 years ago

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Please help me please ​

Please help me please