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OLEGan [10]
3 years ago
10

Write the equation for g(x)

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

Step-by-step explanation:

g(x) = (x+4)² - 5

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Please. Help me solve this
nikklg [1K]

Answer:

1 < a < 13/5

Step-by-step explanation:

2 < 2a - 3(1 -a) < 10

2 < 2a - 3 + 3a < 10

2 < 5a - 3 < 10

2 + 3 < 5a - 3 + 3 < 10 + 3

5 < 5a < 13

5/5 < 5a/5 < 13/5

1 < a < 13/5

5 0
3 years ago
321m ____ .0321 km <br><br> Is it <br> &lt;<br> &gt;<br> =
Neporo4naja [7]

Answer:

=

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
8 Line in the xy-plane contains points from each of Quadrants II, III, and IV, but no points from Quadrant I. Which of the follo
iren2701 [21]

Answer:

The correct option is D.

Step-by-step explanation:

The slope of a line is the change in y with respect to x.

m=\frac{y_2-y_1}{x_2-x_1}

If the slope of a line is undefined it means it is a vertical line and a vertical line  can not passes through three quadrants. So, option A is incorrect.

If the slope of a line is 0 it means it is a horizontal line and a horizontal line  can not passes through three quadrants. So, option B is incorrect.

If the slope of a line is positive it means the value of y increases as x increases.

Since it is an increasing line, therefore after a certain period both x and y will positive. It means the line will passes through first quadrant. So, option C is incorrect.

If the slope of a line is negative it means the value of y decreases as x increases. It can passes through each of Quadrants II, III, and IV.

Therefore the correct option is D.

6 0
3 years ago
10y-12=4<br> Help??? Confused??? Trying to make this twenty letters long lol
ruslelena [56]
If you need to solve for y
10y-12=4
10y=12+4
10y=16
y=16/10=8/5=1 3/5 or 1.6
4 0
4 years ago
Read 2 more answers
Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 12 \sqrt{15 }  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 5 \sqrt{15}

7 0
3 years ago
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