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ANTONII [103]
3 years ago
15

HELP PLEASEE EMERGENCY I WILL GIVE BRAINIEST

Mathematics
2 answers:
galina1969 [7]3 years ago
8 0

Ok as you can see for the x row, the number increase by 1.

For the y row, it increase by 2.

So your slope will be 1/2 and it’s positive sine both x and y is positive.

Irina18 [472]3 years ago
4 0

Answer:

The answer is 2

Step-by-step explanation:

-3+1/-1+0 = -2/-1 = 2 .

Good luck .

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is Justin went shopping for school clothes if the item cost $150 and he received a 10% discount what is the final price of his p
ASHA 777 [7]

Answer:

$135

Step-by-step explanation:

We can answer this by multiplying $150 by (1.00 - 0.10), or by 0.90:

0.90($150) = $135.

Note that 1.00($150) = $150 (full price)

and that 0.10($150) = $15 (discount)

and that (0.90)($150 = $135 (the fastest way to calculate the final (sale) price.

6 0
3 years ago
Read 2 more answers
how many license plates can you make when a license plate consists of 6 out of 26 alphabetical letters each of which can be repe
UkoKoshka [18]
Idk if this is right bc it’s just a guess but maybe 156 bc that’s 26x6
4 0
4 years ago
George brought a shirt and a pair of pants at a clothing store. The pants cost $5.30 more than the shirt, and he used a $15 off
Ierofanga [76]
The answer in B. 21.22
4 0
4 years ago
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If you wanted to make a game where you pay $5 if you can't guess a random dogs weight within 16lbs what payout should you offer
ella [17]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

The population std. dev of the dog weight=8

\sigma=8\\\\P(\text{guess with in 16 lbs}) = P(|X-\mu|\leq 16)\\\\=P(-2 \leq Z \leq 2) = 0.9544\\\\

Calculating the payout w s.t:

E[netpay]=0=(-5) \times 0.9544+w\times (1-0.9544)\\\\ w =(5 \times \frac{0.9544}{1-0.9544}) =\$ 104.65

therefore, we assume that the weight of the dog is a normal distribution with std. deviation that is 8.

4 0
3 years ago
I need help pleaseeeee Prove that: 12^13–12^12+12^11 is divisible by 7 and 19. BTW in format ______*7*19 :D
iragen [17]

Each term has a common divisor of 12^{11}:

12^{13}-12^{12}+12^{11}=12^{11}(12^2-12+1)=12^{11}\cdot133

133 = 7*19, so the number in the blanks is 12^{11}.

3 0
3 years ago
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