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3 years ago

Kristen worked 39 hours in 6 days

Mathematics

2 answers:

Fittoniya [83]3 years ago

5 0

<h2>39/6 = 6.5</h2><h2 /><h2>6 hours 30 minutes</h2>

velikii [3]3 years ago

3 0

Answer: 6 hours and 30 min. or 6.5

Step-by-step explanation: divide 39 by 6 you get 6.5 then (.5) is actually going to be half an hour because half an hour is just 30 minutes

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Explain how to divide 3/4 ÷ 3/8 by using reciprocal of 3/8

sertanlavr [38]

The reciprocal of 3/8 would be 8/3 (basically reversing the numbers).

When dividing fractions, you can just multiply the first fraction by the reciprocal of the second fraction instead of dividing by the second fraction.

3/4 ÷ 3/8

= 3/4 × 8/3

Simplifying gives us the final answer:

= 2

Let me know if you need any clarifications, thanks!

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3 years ago

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Lapatulllka [165]

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3 years ago

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3 years ago

Read 2 more answers

Lizzie rolls two dice. What is the probability that the sum of the dice is:

zhenek [66]

Answer:

$A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\$

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A) = \dfrac{12}{36} = \dfrac{1}{3}$

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)} Count 1

Possible cases for sum 3: {(1,2), (2,1)} Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)} Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)} Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

$P(B) = \dfrac{15}{36} = \dfrac{5}{12}$

C. Divisible by 3 and less than 7:

$P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}$

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

$P(A \cap B) = \dfrac{7}{\text{36}}$

5 0

3 years ago

A 3 cm x 3 cm rectangle sits inside a circle with radius of 4 cm.

Ivanshal [37]

Step-by-step explanation:

you did not show us the picture or described what the shaded area is.

I assume it is the area of the circle without the inner square (as the "rectangke" is actually a square, because its sides are equally long).

so, we need to calculate the area of the circle and subtract the area of the square.

the area of the square is 3×3 = 9 cm².

the area of the circle is

pi×r²

with r being the radius.

so,

pi×4² = pi×16 = 16pi

the shaded area is then

16pi - 9 = 41.26548246... cm² ≈ 41.27 cm²

nothing of the answer options seems to be in that area, so maybe my assumption about the shaded area is wrong. or the specified answer options are mistyped. or both.

anyway, without additional information that is the best I can do.

8 0

2 years ago