All categories

3 years ago

HELLPPPP PLEASE I WILLL MARK YOU BRILL

Mathematics

2 answers:

anygoal [31]3 years ago

7 0

Answer:

Step-by-step explanation:

71-6=65

65/5=13

therefore the answer is 13

s344n2d4d5 [400]3 years ago

5 0

5d + 6 = 71

5d = 71 - 6

5d = 65

d = 65/5

d = 13

You might be interested in

Let the function f(x) have the form f(x) = Acos(x - C). To produce a graph that

Ugo [173]

Answer:

C=2

Step-by-step explanation:

Because I got it correct in AP3X

7 0

2 years ago

Please solve this.<br>..

pentagon [3]

Slope = (y2 - y1) / (x2 - x1)
Slope = -26 - (-14) / 8-4
Slope = -12 / 4
Slope = -3

3 0

2 years ago

What is 2x4+3x4x3x3x2

musickatia [10]

The correct answer is 224.

8 0

3 years ago

Read 2 more answers

A church group set off from their church at 10:00AM for the forest. The group noted that

Anna71 [15]

Answer:

11l:50

Step-by-step explanation:

110 min = 1 hour and 50 minutes

6 0

8 months ago

A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m

Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

Let the weight of first alloy used be $x$ in pounds and the weight of second alloy used be $y$ in pounds.

Total weight = $46\text{ }pounds=x+y$ $-(i)$

Total weight of copper = $37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }$

$\dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702$ $-(ii)$

Subtracting 34 times first equation from second equation,

$34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds$

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0

3 years ago