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irga5000 [103]
3 years ago
13

A painter is using a 8-foot ladder to paint a house. The painter places the ladder 6 feet from the house. How high up the wall d

oes the ladder reach?
Mathematics
1 answer:
9966 [12]3 years ago
5 0

Step-by-step explanation:

step 1. This is a right triangle where a^2 + b^2 = c^2 (c is the hypotenuse).

step 2. a^2 + 6^2 = 8^2.

step 3. a^2 = 64 - 36.

step 4. a^2 = 28.

step 5. a (the ladder height along the wall) = sqrt (28) where sqrt is the square root.

<u>step</u><u> </u><u>6</u><u>.</u><u> </u><u>sqrt</u><u>(</u><u>2</u><u>8</u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>(</u><u>sqrt</u><u>(</u><u>7</u><u>)</u><u>)</u><u>.</u>

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Answer:

P= 456 = 2X +2Y    (1)

And for this case we know the following condition "The length of the field is 7 yards less than quadruple the width" and we can write this :

X = 4Y -7

And replacing into equation (1) we got:

456= 2(4Y-7) +2Y

456 = 8Y -14 +2Y

456 = 10Y-14

Adding 14 in both sides we got:

456+14 = 10Y

And dividing 10 on both sides we got:

Y=\frac{470}{10}= 47

And then we can solve for X and we got:

X= 4*47 -7=181

Step-by-step explanation:

For this case we can set up the following notation:

X represent the lenght

Y represent the width

And since we have a rectangular playing filed the perimeter is given by:

P= 456 = 2X +2Y    (1)

And for this case we know the following condition "The length of the field is 7 yards less than quadruple the width" and we can write this :

X = 4Y -7

And replacing into equation (1) we got:

456= 2(4Y-7) +2Y

456 = 8Y -14 +2Y

456 = 10Y-14

Adding 14 in both sides we got:

456+14 = 10Y

And dividing 10 on both sides we got:

Y=\frac{470}{10}= 47

And then we can solve for X and we got:

X= 4*47 -7=181

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Answer:

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Step-by-step explanation:

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PLEASE HELP WITH THIS QUESTION!!! I'm stuck on it. I can't figure it out. I will mark brainliest if you are correct.
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