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IgorC [24]
3 years ago
11

How do I solve this??

Mathematics
1 answer:
Keith_Richards [23]3 years ago
5 0

Answer:

16q^(2)m^(4)p^(4)

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If f(x)=3x-1 and g(x)=x+2,find (f-g)(x)
oksian1 [2.3K]

Answer:

\large\boxed{(f-g)(x)=2x-3}

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)\\\\f(x)=3x-1,\ g(x)=x+2\\\\\text{substitute:}\\\\(f-g)(x)=(3x-1)-(x+2)\\\\=3x-1-x-2\qquad\text{combine like terms}\\\\=(3x-x)+(-1-2)\\\\=2x-3

7 0
3 years ago
A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 19 randomly selected pens yield
Romashka [77]

Given Information:  

Probability of shipment accepted = p = 5%

Probability of shipment not accepted = q = 95%

Total number of pens = n = 19

Required Information:  

Probability of shipment being accepted with no more than 2 defective pens = P( x ≤ 2) = ?  

Answer:

P( x ≤ 2) = 0.933

Step-by-step explanation:

The given problem can be solved using Bernoulli distribution  which is given by

P(n, x) = nCx pˣqⁿ⁻ˣ  

The probability of no more than 2 defective pens means

P( x ≤ 2) = Probability of 0 defective pen + Probability of 1 defective pen + Probability of 2 defective pens

P( x ≤ 2) = P(0) + P(1) + P(2)

For P(0) we have p = 0.05, q = 0.95, n = 19 and x = 0

P(0) = 19C0(0.05)⁰(0.95)¹⁹

P(0) = (1)(1)(0.377)

P(0) = 0.377

For P(1) we have p = 0.05, q = 0.95, n = 19 and x = 1

P(1) = 19C1(0.05)¹(0.95)¹⁸

P(1) = (19)(0.05)(0.397)

P(1) = 0.377

For P(2) we have p = 0.05, q = 0.95, n = 19 and x = 2

P(2) = 19C2(0.05)²(0.95)¹⁷

P(2) = (171)(0.0025)(0.418)

P(2) = 0.179

Therefore, the required probability is

P( x ≤ 2) = P(0) + P(1) + P(2)

P( x ≤ 2) = 0.377 + 0.377 + 0.179

P( x ≤ 2) = 0.933

P( x ≤ 2) = 93.3%

Therefore, the probability that this shipment is accepted with no more than 2 defective pens is 0.933.

8 0
3 years ago
10/12 - 11/12=???<br><br> I just want to correct my homework.
tangare [24]

Answer:

-1/12

Step-by-step explanation:

you jus gotta substract and jawnt uerme! i know you got dis wrong, dont bluff cutie...

5 0
3 years ago
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Evaluate: 3y + 1 = 13 + 4y<br> **What do you move first?!**
yan [13]

Answer: isolate the variable

Step-by-step explanation:

5 0
3 years ago
Which condition would prove ΔDEF ∼ ΔJKL?
Svet_ta [14]

Step-by-step explanation:

DE : JK

= 21 : 7

= 1 : 3

<h3>#CMIIW</h3>
3 0
3 years ago
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