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Butoxors [25]
3 years ago
14

Francisco has a cylindrical barrel 3 feet tall that he uses to collect rainwater. The barrel is not empty when rain begins to fa

ll at a steady rate. Francisco checks the level 2.5 hours after the rain begins falling and finds that the water level in the barrel is 31.5 inches. He checks again 2.5 hours after his first check and finds that the water level is 32.5 inches. By how many inches does the water level increase for each additional hour of rainfall?
Mathematics
1 answer:
Goryan [66]3 years ago
3 0

Answer:

0.4 inches per hour

Step-by-step explanation:

2.5 hrs = 31.5 in

5 hrs = 32.5

that's 1 inch in 2.5 hours

or

1/2.5 = 0.4 inches per hour

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Solve the equation 5(x + 2) = 6x + 3x − 14, and show your work.
amm1812

Answer:

X=6

Step-by-step explanation:

5(x+2)=6x+3x−1

<u><em>Step 1: Simplify both sides of the equation.</em></u>

5(x+2)=6x+3x−14

(5)(x)+(5)(2)=6x+3x+−14(Distribute)

5x+10=6x+3x+−14

5x+10=(6x+3x)+(−14)(Combine Like Terms)

5x+10=9x+−14

5x+10=9x−14

<u><em>Step 2: Subtract 9x from both sides.</em></u>

5x+10−9x=9x−14−9x

−4x+10=−14

<u><em>Step 3: Subtract 10 from both sides.</em></u>

−4x+10−10=−14−10

−4x=−24

<u><em>Step 4: Divide both sides by -4.</em></u>

−4x / -4= −24 / −4

x=6

8 0
3 years ago
Read 2 more answers
A lay came to the market to sell eggs . We first customer bought 1/2 of all her eggs and 1/2 of an egg. Her second customer boug
Bezzdna [24]

Given:

First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg.

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.

At this point she had sold all her eggs.

To find:

The number of egg the lady have when she came to the market.

Solution:

Let x be the number of egg that the lady have when she came to the market.

First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg. So, the number of remaining eggs after first customer is

x-\dfrac{1}{2}x-\dfrac{1}{2}=\dfrac{x}{2}-\dfrac{1}{2}

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.  So, the number of remining egg after second customer is

\text{Remaining eggs}=\dfrac{x}{2}-\dfrac{1}{2}-(\dfrac{x}{2}-\dfrac{1}{2})\times \dfrac{1}{2}-\dfrac{1}{2}

=\dfrac{x}{2}-\dfrac{1}{2}-\dfrac{x}{4}+\dfrac{1}{4}-\dfrac{1}{2}

=(\dfrac{x}{2}-\dfrac{x}{4})+(-\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{2})

=(\dfrac{2x-x}{4})+(\dfrac{-2+1-2}{4})

=\dfrac{x}{4}-\dfrac{3}{4}

At this point she had sold all her eggs. It means the remining eggs is 0.

\dfrac{x}{4}-\dfrac{3}{4}=0

\dfrac{x}{4}=\dfrac{3}{4}

Multiply both sides by 4.

x=3

Therefore, the lady came to the market is with 3 eggs.

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3 years ago
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Dmitry [639]

Answer:

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Step-by-step explanation:

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3 years ago
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Find the sum of the A.P:8,-3,-2,-7,-12....up to n terms​
Ira Lisetskai [31]

Answer:

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Step-by-step explanation:

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[the second term should be +3 or else it wont form AP series]

first term in the series: 8

common difference : 3-8 = -5

total terms : n

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a: first term

d: common difference

n : total terms

  • by substituting value in the above formula,
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\frac{n}{2} [16+(n-1)(-5)]

\frac{n}{2} [16+(n-1)(-5)]

\frac{n}{2} [16+-5n+5]

\frac{n}{2} [21+-5n]

=\frac{21n}{2} -\frac{5n^{2} }{2}

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4 years ago
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4 years ago
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