Answer:
X=6
Step-by-step explanation:
5(x+2)=6x+3x−1
<u><em>Step 1: Simplify both sides of the equation.</em></u>
5(x+2)=6x+3x−14
(5)(x)+(5)(2)=6x+3x+−14(Distribute)
5x+10=6x+3x+−14
5x+10=(6x+3x)+(−14)(Combine Like Terms)
5x+10=9x+−14
5x+10=9x−14
<u><em>Step 2: Subtract 9x from both sides.</em></u>
5x+10−9x=9x−14−9x
−4x+10=−14
<u><em>Step 3: Subtract 10 from both sides.</em></u>
−4x+10−10=−14−10
−4x=−24
<u><em>Step 4: Divide both sides by -4.</em></u>
−4x / -4= −24 / −4
x=6
Given:
First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg.
Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.
At this point she had sold all her eggs.
To find:
The number of egg the lady have when she came to the market.
Solution:
Let x be the number of egg that the lady have when she came to the market.
First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg. So, the number of remaining eggs after first customer is

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg. So, the number of remining egg after second customer is





At this point she had sold all her eggs. It means the remining eggs is 0.


Multiply both sides by 4.

Therefore, the lady came to the market is with 3 eggs.
Answer:
D
Step-by-step explanation:
hey
Answer:

Step-by-step explanation:
- given ap series : 8,3,-2,-7,-12....up to n terms
[the second term should be +3 or else it wont form AP series]
first term in the series: 8
common difference : 3-8 = -5
total terms : n
- the formula for sum of n terms in an ap =
![\frac{n}{2} [2a+(n-1)d]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B2a%2B%28n-1%29d%5D)
a: first term
d: common difference
n : total terms
- by substituting value in the above formula,
- sum of the A.P:
![\frac{n}{2} [2(8)+(n-1)-5]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B2%288%29%2B%28n-1%29-5%5D)
![\frac{n}{2} [16+(n-1)(-5)]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B%28n-1%29%28-5%29%5D)
![\frac{n}{2} [16+(n-1)(-5)]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B%28n-1%29%28-5%29%5D)
![\frac{n}{2} [16+-5n+5]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B-5n%2B5%5D)
![\frac{n}{2} [21+-5n]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B21%2B-5n%5D)
=
So divide factions ex: 6/2 divide 3/2 will bring down the first faction 6/2 then the always flip the second faction 2/3 to make it 2/3 the you have 6/2 divide 2/3, now you multiple 6/2 times 2/3 so how many times does 3 go in6 so the 3 will be 1 and the 6 will be 2 now 2 and 2 both will come 1 because 2 goes in both of them 1 time and the answer is 2/1