AnswerYES
Explanation:
The data is consistent with the model because they are predicted patterns based on probabilities.
Answer:
2 molecules of ATP and 2 molecules of NADH
Explanation:
Glycolysis is the first step of cellular respiration (break down of glucose to extract energy) which occurs in the cytoplasm. Glycolysis is a pathway common to all living organisms- prokaryotes and eukaryotes, as it does not require oxygen to occur.
Glycolysis occurs in two major phases (ten steps) requiring 10 enzymes catalyzing each step; the energy-requiring phase and the energy-requiring phase.
In the energy-requiring phase, the starting molecule (glucose) gets rearranged in a series of chemical reactions, and two phosphate groups gets attached to it producing fructose-1,6-bisphosphate which is unstable, This modified sugar then splits in half due to its instability to form two different but inter-convertible phosphate-bearing three-carbon sugars (Dihydroxyacetonephosphate, DHAP and Glyceraldehyde-3-phosphate, G3P). Because the phosphates used in these steps come from 2 ATP molecules, 2 ATP molecules get used up in this phase
All the DHAP molecules get converted to G-3-P in order to enter the next phase.
In the energy-recovering phase, the 3-carbon sugar (G3P) is converted into another three-carbon molecule called pyruvate, through a series of reactions. In these reactions, two ATP and 1 NADH molecules are made. This recovery phase occurs twice (one for each of the two isomeric three-carbon sugars, DHAP and G3P). Hence, a total of 4 ATP and 2 NADH molecules are produced in this phase.
Overall, Glycolysis converts one glucose (six-carbon) molecule to two pyruvate (three-carbon) molecules and a net release of 2 ATP molecules (4 overall - 2 used) and 2 NADH molecules.
Answer:
Heterozygous dominant (Bb) and homozygous recessive (bb)
Explanation:
This cross involves the gene that codes for color blindness in whales. The allele for no color blindness/normal vision (B) is dominant over the allele for color blindness (b). This means that B will mask the phenotypic expression of b in a heterozygous state (Bb).
According to the question, one of the parents is color blind meaning it possesses the homozygous recessive genotype (bb) while the other parent (pearl) has a normal vision which can either be homozygous dominant or heterozygous dominant since the normal vision allele (B) is dominant.
However, since one of the two offsprings (sons) is also color blind, this implies that the parent with normal vision is heterozygous i.e. contains both dominant and recessive alleles, for the trait. What happens is that, when a bb and Bb parent are crossed, they produce gametes with either a recessive or dominant allele.
The Bb produces gametes with B and b alleles while the bb produces gametes with b and b alleles. When this are crossed using a punnet square, four possible offsprings will be produced with two distinct genotypes: Bb and bb. Hence, this means that there is a 1/2 chance of producing an offspring with the recessive trait from this cross as the case is in the whales.
Oxygen molecules are too small and glucose molecules are quite large than oxygen. So they can't passively disuse inside a cell.
Option C
<h3><u>Explanation:</u></h3>
Glucose molecules are large molecules with a molecular formula of C₆H₁₂O₆ These molecules need special protein channels or transporters called Glucose Transporters or GLUT to make them way through the cell membranes. While smaller molecules like oxygen, carbon dioxide, smaller polar molecules like <em>water</em> or even fat soluble molecules like chloroform and benzene do pass through the membranes easily by means of passive diffusion.
The oxygen molecules are needed inside a human cell for aerobic respiration and glucose molecules are needed because of a respiratory substrate. So Glucose needs receptors and transporters to pass through the membranes.
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