Answer:
306.8 feet
Step-by-step explanation:
Refer the attached figure .
A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m
Referring the image .
AC=ED=160 m
A transit i.e. AE is 6 feet tall.
AE = CD=6 feet
With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°
To Find BC , use tigonometric ratio.





Now, the height of the pole = BC+CD =300.8+6=306.8 feet
Hence the height of the pole is 306.8 feet
Let's call :
x=the number of downloaded standard version
y= the number of downloaded high-quality version
We have : -the high-quality version was downloaded three times as often as the
standard version => 3x=y
-standard version is 2.8 megabytes .the high-quality version is 4.6
MB.The total size downloaded for the two versions was 4482 MB
=> 2.8x+4.6y=4482
Solve for x,y
x=270 , y=810
The answer is 30. You just multiply 51 by (10/17)