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2 years ago

PLEASE HELP ANYONE.....

Mathematics

2 answers:

irga5000 [103]2 years ago

8 0

Answer:

the awnser should have is. b

BigorU [14]2 years ago

6 0

The answer is B.
Just looking at the question we know he needs 18 more stamps.
You can plug in 18 for s in each of the answer choices and see that B is the only one that makes sense

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Solve 24x + 2y = 48 for x

drek231 [11]

Isolate x.
24x = 48 - 2y

Divide by 24.
x = 2 - y/12

3 0

2 years ago

Read 2 more answers

Suppose that f: R --> R is a continuous function such that f(x +y) = f(x)+ f(y) for all x, yER Prove that there exists KeR su

Pachacha [2.7K]

<h2>Answer with explanation:</h2>

It is given that:

f: R → R is a continuous function such that:

$f(x+y)=f(x)+f(y)------(1)$ ∀ x,y ∈ R

Now, let us assume f(1)=k

Also,

f(0)=0

( Since,

f(0)=f(0+0)

i.e.

f(0)=f(0)+f(0)

By using property (1)

Also,

f(0)=2f(0)

i.e.

2f(0)-f(0)=0

i.e.

f(0)=0 )

Also,

f(2)=f(1+1)

i.e.

f(2)=f(1)+f(1) ( By using property (1) )

i.e.

f(2)=2f(1)

i.e.

f(2)=2k

Similarly for any m ∈ N

f(m)=f(1+1+1+...+1)

i.e.

f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)

i.e.

f(m)=mf(1)

i.e.

f(m)=mk

Now,

$f(1)=f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=f(\dfrac{1}{n})+f(\dfrac{1}{n})+....+f(\dfrac{1}{n})\\\\\\i.e.\\\\\\f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=nf(\dfrac{1}{n})=f(1)=k\\\\\\i.e.\\\\\\f(\dfrac{1}{n})=k\cdot \dfrac{1}{n}$

Also,

when x∈ Q

i.e. $x=\dfrac{p}{q}$

Then,

$f(\dfrac{p}{q})=f(\dfrac{1}{q})+f(\dfrac{1}{q})+.....+f(\dfrac{1}{q})=pf(\dfrac{1}{q})\\\\i.e.\\\\f(\dfrac{p}{q})=p\dfrac{k}{q}\\\\i.e.\\\\f(\dfrac{p}{q})=k\dfrac{p}{q}\\\\i.e.\\\\f(x)=kx\ for\ all\ x\ belongs\ to\ Q$

(

Now, as we know that:

Q is dense in R.

so Э x∈ Q' such that Э a seq belonging to Q such that:

$\to x$ )

Now, we know that: Q'=R

This means that:

Э α ∈ R

such that Э sequence $a_n$ such that:

$a_n\ belongs\ to\ Q$

and

$a_n\to \alpha$

$f(a_n)=ka_n$

( since $a_n$ belongs to Q )

Let f is continuous at x=α

This means that:

$f(a_n)\to f(\alpha)\\\\i.e.\\\\k\cdot a_n\to f(\alpha)\\\\Also\\\\k\cdot a_n\to k\alpha$

This means that:

$f(\alpha)=k\alpha$

This means that:

f(x)=kx for every x∈ R

4 0

2 years ago

I got stuck on this question.<br> Use long division to solve

Phantasy [73]

Answer:

5x² +19x +76 +310/(x-4)

Step-by-step explanation:

The process is straightforward. Find the quotient term, multiply it by the divisor and subtract from the dividend to get the new dividend. Repeat until the dividend is a constant (lower-degree than the divisor).

The tricky part with this one is realizing that there is no x-term in the original dividend, so that term needs to be added with a 0 coefficient. The rather large remainder is also unexpected, but that's the way this problem unfolds.

Unlike numerical long division, polynomial long division is simplified by the fact that the quotient term is the ratio of the highest-degree terms of the dividend and divisor. Here, the first quotient term is (5x^3)/(x) = 5x^2.