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3241004551 [841]
3 years ago
9

PLEASE HELP ANYONE.....

Mathematics
2 answers:
irga5000 [103]3 years ago
8 0

Answer:

the awnser should have is. b

BigorU [14]3 years ago
6 0
The answer is B.
Just looking at the question we know he needs 18 more stamps.
You can plug in 18 for s in each of the answer choices and see that B is the only one that makes sense
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How to classify this conic ecwation 4x^2+9y^2-54y-63=0
MArishka [77]
This looks like an ellipse.
Complete the square for y: 9(y²-6y-7)=9(y²-6y+9-9-7)=9((y-3)²-16).
Rewrite the equation:
4x²+9(y-3)²-144=0; 4x²/144+9(y-3)²/144=1; x²/36+(y-3)²/16=1.
Standard equation of an ellipse is (x-h)²/a²+(y-k)²/b²=1, where (h,k) is the origin or centre.
This is the equation of an ellipse with centre (0,3), a=6 and b=4 (semimajor and semiminor axes).
6 0
4 years ago
find two consecutive integers such that the sum of the lager number and 4 times the smaller number is 156
Len [333]
<h2>Answer:   31 & 32</h2>

Step-by-step explanation:

So we first need to assign letters to represent the numbers.

Let 'a' be the larger number and 'b' the smaller.

Now we can use this to write equations that we can solve simultaneously to find both 'a' and 'b'.

according to the question:

a + 4b  = 156  [1]

a - b = 1  [2]   (this is because the integers are consecutive

We can rearrange [2] to make 'a' the subject:     a = b + 1 [3]

We can then substitute [3]  into [1] and solve for b

(b + 1) + 4b = 156

5b = 155

 b = 31

Now we can find 'a' using [3]

a = 31 + 1

a = 32

4 0
3 years ago
A circle has a radius of 9 inches. The Radius is multiplied by 2/3 to form a second circle. How is the ratio of the areas relate
liraira [26]

Answer:

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{r_{1} }{r_{2}}) ^{2}

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii.

Step-by-step explanation:

Radius of first circle (r_{1}) = 9 inches

Area of first circle = \pi r_{1} ^{2}

Area of first circle = 9 × 9 × π = 81 π

Now, since the radius is multiplied by 2/3 for from a new circle.

∴ Radius of the second circle = 9 \times \frac{2}{3} = 6\ inches

Area of second circle =  \pi r_{2} ^{2}

Area of second circle = 6 × 6 × π = 36 π

Now,

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81\pi }{36\pi }

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{9}{6}) ^{2} = (\frac{r_{1} }{r_{2}}) ^{2}

∵ (r_{1}) = 9 inches and (r_{2}) = 6 inches

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii. i.e., \frac {radius\ of\ first\ circle)^{2} }{(radius\ of\ second\ circle)^{2} } = \frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)}

8 0
3 years ago
The product of two and a third of a number is eight.<br><br> Please provide equation
maksim [4K]

Answer: let get started

Step-by-step explanation: the sum of two-thirds of a number and eight is equal to the difference of seven-thirds of the same number and two

8 0
3 years ago
After a 15% reduction, the sale price of a car is £13175. What was the
OlgaM077 [116]

Answer:

<u>The original price of the car was 11198.75</u>

Step-by-step explanation:

Hope it helps!

6 0
2 years ago
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