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DochEvi [55]
3 years ago
12

You are thinking of hiring a security monitoring service. You can pay a flat rate of $55 per month or pay $210 per incident. You

expect to average one incident per three months. Which plan will be cheaper for you?
a) Per incident

b) Flat rate
Mathematics
1 answer:
faltersainse [42]3 years ago
3 0

Answer:

Flat rate

Step-by-step explanation:

Per incident, you'll play 210 dollars

Flat rate, you'll pay 55 dollars per month

Based on the expected average

You'll either pay $210 for the incident or $165 (flat rate amount for 3 months)

Therefore, flat rate will be cheaper

Hope this helps!

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The equation for the cost in dollars of producing computer chip is y = .000015x^2 - .03x +35. Where X is the number of chips pro
lilavasa [31]

Answer:

The equation for the cost in dollars of producing computer chips

The equation for the cost in dollars of producing computer chips is C = 0.000015x^2 - 0.03x + 35, where x is the number of chips produce. Find the number of chips that minimizes the cost.

Step-by-step explanation:

5 0
3 years ago
Tell whether the sequence 12, 4, -4, -12, -20, ... is arithmetic
Shkiper50 [21]

Answer:

yes, it is arithmetic as the common difference is -8

8 0
3 years ago
Read 2 more answers
Consider the function f(x, y) = x2 + xy + y2 defined on the unit disc, namely, d = {(x, y)| x2 + y2 ≤ 1}. use the method of lagr
Pani-rosa [81]
First we note that the partial derivatives vanish simultaneously at one point:

\begin{cases}f_x=2x+y=0\\f_y=x+2y=0\end{cases}\implies(x,y)=(0,0)

so there is one critical point within the region D.

The Lagrangian is

L(x,y,\lambda)=x^2+xy+y^2+\lambda(x^2+y^2-1)

and has partial derivatives

L_x=2x+y+2\lambda x
L_y=x+2y+2\lambda y
L_\lambda=x^2+y^2-1

Set each partial derivative to 0 to find the possible critical points within the disk D. Then we notice that

yL_x=2xy+y^2+2\lambda xy=0
xL_y=x^2+2xy+2\lambda xy=0
L_\lambda=0\implies x^2+y^2=1

\implies xL_y-yL_x=x^2-y^2=0

Since x^2+y^2=1, we have

x^2-y^2=x^2+y^2-2y^2=0\implies1=2y^2\implies y^2=\dfrac12\implies y=\pm\dfrac1{\sqrt2}

And since x^2-y^2=0, or x^2=y^2, we also have

x=\pm\dfrac1{\sqrt2}

So we have four possible additional critical points to consider:

f(0,0)=0
f\left(-\dfrac1{\sqrt2},-\dfrac1{\sqrt2}\right)=\dfrac32
f\left(-\dfrac1{\sqrt2},\dfrac1{\sqrt2}\right)=\dfrac12
f\left(\dfrac1{\sqrt2},-\dfrac1{\sqrt2}\right)=\dfrac12
f\left(\dfrac1{\sqrt2},\dfrac1{\sqrt2}\right)=\dfrac32

It should be clear enough which of these correspond to the absolute extrema of f over D.
8 0
3 years ago
I need help solving this​
max2010maxim [7]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
This prism has a surface area of 172 cm². What would the surface of the prism be if each dimension was tripled? ( Scale factor i
Alex787 [66]

Answer:

1356 cm²

Step-by-step explanation:

Each dimension gets multiplied by 2, so the new dimensions are

changed from 2x8x7 to 6x24x21

There are 6 faces to the prism,

The area of the front and back are 6x21 = 126.  There are 2 of them for a total area of 126x2 = 252 cm²

The are of the left and right sides are 24x21 = 504.  There are 2 of them for a total area of 504x2 = 1008 cm²

The area of the top and bottom are 6x24 = 144, there are 2 of them for a total area of 144x2 = 288 cm²

The total surface area is 252 + 1008 + 96 = 1356 cm²

7 0
3 years ago
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