All categories

2 years ago

Find the value of x.

Mathematics

1 answer:

scZoUnD [109]2 years ago

7 0

Answer:

x = 120 degress

Step-by-step explanation:

I can help with more, I have the answers.

You might be interested in

Bobcat park is a rectangular park with an area of 5 1/5 square miles.Its width is 1 19/20 miles. How long is the park

mel-nik [20]

area = length times width, so length = area / width

5 1/5 mi^2 5.2 mi^2

Here, length = ------------------- = --------------- = 2.66666... mi = 2 2/3 mi (answer)

1 19/20 mi 1.95 mi

4 0

3 years ago

the first Indianapolis 500 auto race took place in 1911. the winning car covered the 500 miles in 6.7 hours. what was the winnin

Vesna [10]

Average speed = (distance covered) / (time to cover the distance)

   = (500 miles) / (6.7 hours)

   = (500 / 6.7) (mile/hour)

   = 74.63 miles per hour.

I imagine there were quite a number of pit stops included in that.

This is faster than I expected when I first read your question.
That's really gettin' with it for cars in 1911 !

4 0

3 years ago

An electrician has 4.1 meters of wire how many strips 7/10 m can he cut . How much wire will he have left

kogti [31]

7/10 m= 0.7 m

4.1÷0.7=5.85

You would round down 5.85 to just 5, because he cannot cut less than a whole strip.

To find the exact amount of wire used in 5 strips:

5×0.7= 3.5

4.1-3.5= 0.6 m will be leftover.

8 0

3 years ago

What is the value of 8 to the power of 0

Triss [41]

Answer:

Step-by-step explanation:

3 0

3 years ago

Una compañía de telefonía móvil en expansión ha gestionado durante el trimestre que finaliza ochocientas cincuenta mil llamadas

NISA [10]

Answer:

$2,050,000\ daily\ calls$

Step-by-step explanation:

<u><em>The question in English is </em></u>

An expanding mobile phone company handled eight hundred and fifty thousand calls a day during the quarter. In the next quarter it expects to reach one million and increase quarterly by the same amount over the next two years. How many daily calls do you expect to handle in two years?

Let

x ----> the number of quarter

y ---> number of daily calls

we know that

we have the points

(0,850,000) and (1,1,000,000)

Find the slope m

$m=(1,000,000-850,000)/(1-0)=150,000\ daily\ calls$

The linear equation that represent this situation is

$y=150,000x+850,000$

How many daily calls do you expect to handle in two years?

In two years there are 8 quarterly

For x=8

substitute

$y=150,000(8)+850,000=2,050,000\ daily\ calls$

7 0

3 years ago