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valentinak56 [21]
3 years ago
5

Express the confidence interval (63.3%, 79.1%) in the form of ˆp ± ME. ___% ± ___%

Mathematics
1 answer:
inessss [21]3 years ago
4 0

Answer:

p \± ME \to 71.2\%  \± 7.9\%

Step-by-step explanation:

Given

(63.3\%,79.1\%)

Required

Express in form of: p \± ME

First, calculate the midpiont (p)

p = \frac{63.3\% + 79.1\%}{2}

p = \frac{142.4\%}{2}

p = 71.2\%

The margin of error (ME) is:

ME =79.1\% - 71.2\%

ME =7.9\%

So, we have:

p \± ME \to 71.2\%  \± 7.9\%

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