This is the concept of algebra, given that the room is 150 sq. feet, the dimensions of the room can be found as follows;
Suppose the room is a perfect square, the length=width= x ft
therefore the are will be:
area=length*width
=x*x=x^2 sq. ft
hence;
x^2=150
getting the square root of both sides we get:
sqrt x^2=sqrt150
x=sqrt150
x=12.248 ft
x=12 ft (to the nearest feet)
9514 1404 393
Answer:
- 75 adult tickets
- 125 child tickets
Step-by-step explanation:
Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...
8a +5(200 -a) = 1225
3a = 225 . . . . . . . . . . subtract 1000, simplify
a = 75 . . . . . . . . . . . . .divide by 3
200 -a = 125
75 adult ($8) and 125 child ($5) tickets were sold.
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<em>Additional comment</em>
The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.
There are 16 total marbles with 6 blue ones.
Picking a blue one first is 6/16, reduces to 3/8
After picking a blue one first there are 5 blue ones left and 15 total marbles, so picking another blue would be 5/15, reduces to 1/3
The probability of picking both blue, multiply the two together:
3/8 x 1/3 = 3/24 = 1/8 = 0.125 x 100 = 12.5%
