The answer is number 3. y=(-2/3)x +5
The answer is 100N all you have to do is multiply 5 by 20.
Answer:
The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
Step-by-step explanation:
The average speed is given by the following equation:

From 10A.M. to noon.
You traveled at 50mph during 2 hours. So how long you traveled?



You traveled 100 miles.
What was your average speed over the time interval from 9 A.M. to noon
From 9 A.M. to 10 A.M, you did not travel.
From 10 P.M. to noon, 100 miles.
So 100 miles during 3 hours.

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
That will be;
5/6 x 3/10
15/60
3/12
1/4
Hope i helped
Answer:
The number of bacteria after
will be 
Step-by-step explanation:
Given the initially 30 bacteria present in the culture.
Also, the number of bacteria got doubled every hour.
So, using the equation

Where
is number of bacteria after
hours.
is bacteria present initially.
is the common ration, in our problem it is given that bacteria doubles every hour. So, 
And
is the number of hours. In our problem we need amount of bacteria at the end of
hours. So, 
Plugging values in the formula we get,

So, number of bacteria after
will be 