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guapka [62]
3 years ago
11

What is 6 3/4 - 2 2/3

Mathematics
1 answer:
likoan [24]3 years ago
5 0

Answer:

In fraction form it is 4 1/12

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Consider the following IP problem:
Liono4ka [1.6K]

Answer:

(3,0)

Step-by-step explanation:

The integer points which fall in the common region bounded by the lines are

(0,2),(2,3),(3,0)

Since, one of the points is (2.22...,3.11....) we round it to (2,3)

If we round up then the point will be (3,4) which does not fall in the bounded region.

Also x_1\geq 0 and x_2\geq 0 no negative values are considered.

Applying in the values in the LP problem Z=5x_1+x_2

Z=5\times 0+2\\\Rightarrow Z=2

Z=5\times 2+3\\\Rightarrow Z=13

Z=5\times 3+0\\\Rightarrow Z=15

So, the LP problem is maximum at point (3,0).

7 0
3 years ago
Your dad bought you a pair of sneakers for $52. The sneakers were 20% off. What was the original price of the sneakers?
Leviafan [203]

Answer:

p - 20%p = $52

p - 20p/100 = $52

p - p/5 = $52

p - 0.2p = $52

0.8p = $52

p = $52 : 0.8

p = $ 65

8 0
3 years ago
Help pleaseeeee it’s a math question
Illusion [34]

Answer:

c(x + y) = a^2 + b^2

Step-by-step explanation:

All you have to do is cross multiply.

cx = a^2

cy = b^2

Add the equations.

cx + cy = a^2 + b^2

c(x + y) = a^2 + b^2

3 0
3 years ago
Read 2 more answers
Help on this please helppp
LiRa [457]

Answer:

7

Step-by-step explanation:

8 0
3 years ago
Find the area of the shaded portion intersecting between the two circles.
Zolol [24]
Look at the picture.

ΔABC and ΔBDC are <span>equilateral triangles.

Area of sector of a circle:
\dfrac{60^o}{360^o}=\dfrac{1}{6}\\\\area\ of\ a\ circle\\A_O=\pi r^2;\ r=4\\A_O=\pi\cdot4^2=16\pi\\\\A_s=\dfrac{1}{6}A_O\to A_s=\dfrac{1}{6}\cdot16\pi=\boxed{\dfrac{8}{3}\pi}

Area of the triangle ABC:
A_\Delta=\dfrac{a^2\sqrt3}{4};\ a=4\\\\A_\Delta=\dfrac{4^2\sqrt3}{4}=\dfrac{16\sqrt3}{4}=\boxed{4\sqrt3}

Area of the shaded portion:
A=2(A_s-A_\Delta)\\\\\boxed{A=2\left(\dfrac{8}{3}\pi-4\sqrt3\right)\approx2.89}
</span>

3 0
3 years ago
Read 2 more answers
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