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Jlenok [28]
3 years ago
5

32 students were asked which of the sciences they enjoy the most. 4 of the boys said they enjoy Physics. The ratio between boys

and girls is 1 : 1 . The probability of picking a girl at random who enjoys Chemistry is 0.25 . Twice as many of the boys said they enjoy Chemistry compared to the girls. The ratio of students who said they enjoyed Physics, Biology and Chemistry was 5 : 5 : 6 respectively.
Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

Step-by-step explanation: Total number of students = 32

Total number of ratio of students that enjoy Physics, Biology and Chemistry = 5 + 5 + 6 = 16

Number of boys that enjoy the three subjects = 16

Number of girls that enjoy the three subjects = 16

Number of students that enjoy Physics = 5/16 X 32 = 10

Number of students that enjoy Biology = 5/16 X 32 = 10

Number of students that enjoy Chemistry = 6/16 X 32 = 12

If number of boys that enjoy Physics = 4

∴ Number of girls that enjoy Physics = 10 - 4 = 6

The probability of girls that enjoy Chemistry = 0.25 = 1/4

∴ The number of girls that enjoy Chemistry = 1/4 X 12 = 3

Hence, the number of boys that enjoy Chemistry = 12 - 3 = 9

Number of boys that enjoy Biology = 9 + 4 - 10 = 13 - 10 = 3

∴ Number of girls that enjoy Biology = 10 - 3 = 7

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Answer:

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Part b) see the explanation

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Step-by-step explanation:

<u><em>The complete question is</em></u>

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

Part A) Use words and an equation to represent this problem

Let

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we know that

The linear equation in slope intercept form is equal to

a=mg+b

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In this problem we have

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Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

For g=0 ----> a=4(0)+10=\$10

For g=1 ----> a=4(1)+10=\$14

For g=2 ----> a=4(2)+10=\$18

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\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]

Part c) Use the values from your table to draw a graph

we have the ordered pairs

(0,10),(1,14),(2,18),(3,22),(4,26)

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