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creativ13 [48]
2 years ago
7

What is the perimeter of JKL?

Mathematics
1 answer:
Virty [35]2 years ago
8 0

Answer:

The perimeter of JKL is 60 units.

Step-by-step explanation:

The two tangents of a circle formed by a vertex outside the circle will always be the same distance, this means that JA = JB = 13, LA = LC = 7, and KB = KC = 10. JL = JA + LA = 20, KL = LC + KC = 17, and JK = JB + KB = 23. So the perimeter of triangle JKL is 20 + 17 + 23 = 60 units.

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Brendan is 18 years younger than Miranda. 8 years ago, Miranda was 2 times Brendan’s age. How old is Brendan now
AlexFokin [52]

Answer:

I think Brendan is 22? I'm not sure and im 70% sure im wrong!

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7 0
3 years ago
The amount of money in a saving account increase from $250 to $270 what is the precent increase of the money in the savings acco
saveliy_v [14]

Answer:

8%

Step-by-step explanation:

percent increase = [ (difference between initial value and final value) ÷ initial value] x 100

⇒ percent increase = [ (270 - 250) ÷ 250] x 100 = 8%

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2 years ago
Read 2 more answers
What is the area of the polygon
Rina8888 [55]
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Solve x+2<-4 or -5x<-15
andreev551 [17]
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4 0
3 years ago
100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
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