The base of a logarithm should always be positive and can't be equal to 1, so the domain is 0 < <em>x</em> < 1 or <em>x</em> > 1.
Write both sides as powers of 1/<em>x</em> :
Recall that 
, so that
Take the 5th root of both sides, recalling that 3⁵ = 243, so
![x=\sqrt[5]{\dfrac1{243}}=\boxed{\dfrac13}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B5%5D%7B%5Cdfrac1%7B243%7D%7D%3D%5Cboxed%7B%5Cdfrac13%7D)
Answer:
x ≈ 15.0 ft
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Trigonometry</u>
- tan∅ = opposite over adjacent
Step-by-step explanation:
<u>Step 1: Define</u>
Angle = 28°
Opposite leg of angle = 8 ft
Adjacent leg of angle = x ft
<u>Step 2: Find </u><em><u>x</u></em>
- Substitute: tan28° = 8/x
- Multiply <em>x </em>on both sides: xtan28° = 8
- Divide tan28° on both sides: x = 8/tan28°
- Evaluate: x = 15.0458
- Round: x ≈ 15.0 ft
Answer:
8/18=4/9
Step-by-step explanation:
since it there is 1/6 for red marbles and 5/18 for blue marbles it works because it is 8*9=72 for the denominator and 4*3=12 so it is 12/72=1/6 and for blue it is 5/18 because it is 5*4=20 and 20/72=10/36=5/18 so it is 1/6+5/18=8/18=4/9
.h.i. i think i know the answer
