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creativ13 [48]
3 years ago
7

What is the perimeter of JKL?

Mathematics
1 answer:
Virty [35]3 years ago
8 0

Answer:

The perimeter of JKL is 60 units.

Step-by-step explanation:

The two tangents of a circle formed by a vertex outside the circle will always be the same distance, this means that JA = JB = 13, LA = LC = 7, and KB = KC = 10. JL = JA + LA = 20, KL = LC + KC = 17, and JK = JB + KB = 23. So the perimeter of triangle JKL is 20 + 17 + 23 = 60 units.

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Sonbull [250]

Answer:

It's OC

Step-by-step explanation:

Because what it's asking you is what is the distance he's running in that time.because d stands for the amount of distance covered in a second so you need to multiply the seconds against the distance that he covers in that second to get the 100 m that he runs in all

6 0
3 years ago
A group of friends wants to go to the amusement park. They have no more than $165
Oksi-84 [34.3K]

Answer:

17.75x + 5.25 \leq 165

x \leq 9

Step-by-step explanation:

The total cost can be represented by 17.75x + 5.25, where x is the number of people.

They can only spend a maximum of $165, so a less than or equal sign has to be used.

The inequality will be 17.75x + 5.25 \leq 165

Now, solve for x:

17.75x + 5.25 \leq 165

17.75x \leq 159.75

x \leq 9

So, x \leq 9 is the answer, meaning 9 people or less can go to the amusement park.

3 0
2 years ago
Joshua made note of all the bicycles and cars he could see parked or locked on a
Mars2501 [29]

Answer:

56

Step-by-step explanation:

11*4=44

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44+12=56

3 0
2 years ago
Find the inverse function of
shtirl [24]

Answer:

f(x) = 20x - 4 \\ substitute \: y \: for \: f(x) \\ y = 20x - 4 \\ interchange \: x \: and \: y \\ x = 20y - 4 \\ swap \: the \: sides \: of \: the \: equation \\ 20y - 4 = x \\ move \: the \: constant \: to \: the \: right \: hand \\ 20y = x + 4  \\ divide \: both \: sides \: by \: 20 \\ y =  \frac{1}{20} x +  \frac{1}{5}  \\ substitute \: f {}^{ - 1} (x) \: for \: y \\ f {}^{ - 1} (x) =  \frac{1}{20} x +  \frac{1}{5}

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

Thus, domain of f(x): x∈R = range of f¯¹(x)

and range of f(x): x∈R =domain of f¯¹(x)

3 0
2 years ago
jenny is comparing the cost of two packages of socks. one package has 8 pairs for $12. Another package has 3 for $6. Are the rat
Ainat [17]
In order to solve this we need to make on part of both statements equal.

Since 12 is divisible by 6 lets do that.

Multiply everything in the second package by 2.

It then becomes 6 pairs for $12.

So now  have have 6 or 8 pairs for $12.

You are getting a different amount for the same price therefore they are not proportional.
5 0
3 years ago
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