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liq [111]
3 years ago
12

Y=-2x x+y=3 What is the value of x?

Mathematics
2 answers:
Kay [80]3 years ago
6 0

Step-by-step explanation:

x+y=3

y=2x

x+2x=3

x=3-2x

it's your required answer

Yanka [14]3 years ago
3 0

Answer:

x = -3

If you need to find the value of y than substitute x=-3 into equation (1) .

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Step-by-step explanation:

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"5 subtracted from a number is a maximum of 14
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Answer:

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A quadratic function has a line of symmetry at x=-3.5 and zero at -9 what is the distance from the given zero to line of symmetr
g100num [7]

If a quadratic function has zero at x=-9, then point (-9,0) lies on the graph of quadratic function.

A line of symmetry has equation x=-3.5 that is x+3.5=0.

Use formula for the distance from point (x_0,y_0) to the line AX+By+C=0:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}.

Thus,

d=\dfrac{|-9+3.5|}{\sqrt{1^2+0^2}}=5.5.

Answer: the distance is 5.5 units.

4 0
3 years ago
Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T
myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5                          

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

\text{P(at least one head)} = \dfrac{7}{8} = 0.875

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

3 0
3 years ago
Help with these questions
nata0808 [166]
Explaintion is in a file
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3 years ago
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