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Deffense [45]
2 years ago
5

Write the coordinates of the vertices after a rotation of 90 degrees counterclockwise around the origin.

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
5 0

Answer:

U(2, 7) → U'(-7, 2)

V(10, 7) → V'(-7, 10)

W(2, 3) → W'(-3, 2)

Step-by-step explanation:

From the picture attached,

Coordinates of the vertices of the given triangle,

U → (2, 7)

V → (10. 7)

W → (2, 3)

Since rule for the coordinates of a point P(x, y) after a rotation of 90° counterclockwise about the origin is,

P(x, y) → P'(-y, x)

Here point P is the preimage and P' is the image point after rotation.

By this rule,

U(2, 7) → U'(-7, 2)

V(10, 7) → V'(-7, 10)

W(2, 3) → W'(-3, 2)

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The line through (6,-6) with slope 1/2 in point-slope form ?
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Step-by-step explanation:

Point-slope formula:  y - y1 = m(x - x1)

Plug in the numbers: y - -6 = \frac{1}{2}(x-6)

Clear the double negatives: y + 6 = \frac{1}{2}(x - 6)

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Decrypt the word DKA if it was encrypted using an alphabetic Caesar shift cipher that starts with shift 5 (mapping A to F), and
pochemuha

Answer:

YET

Step-by-step explanation:

TO DECRYPT DKA USING THE CAESAR SHIFT CIPHER STARTING WITH 5 SHIFTS.

TO DO THIS DECRYPTION, WE'RE GOING TO LOOP THE ALPHABETS.

D = LOOPING THIS LETTER 5 TIMES, WE HAVE C - B - A - Z - Y.

SO, D IS DECRYPTED AS Y

GOING FURTHER, THE ENCRYPTION SHIFTS BY AN ADDITIONAL SPACE. THIS MEANS, IF THE FIRST "Y" WAS ENCRYPTED IN 5 SPACES TO GET D, AND AN ADDITIONAL SPACE WAS ADDED TO THE NEXT ALPHABET, IT BECOMES 6.

K IS THEN DECRYPTED AS

K = J - I - H - G - F - E

K IS DECRPYTED AS E

GOING FURTHER, THE NEXT WAS ENCRYPTED WITH AN ADDITIONAL SPACE EVEN MORE, SO, A IS DECRPYTED AS

A = Z - Y - X - W - V - U - T.

THUS, DKA IS DECRYPTED AS YET

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3 years ago
What is the Answer to this question
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