Answer:
see explanation
Step-by-step explanation:
To find the x- intercepts set y = 0, that is
- 2x² - 9x + 5 = 0
To factorise the quadratic consider the factors of the product of the coefficient of the x² term and the constant term that sum to give the coefficient of the x- term.
product = - 2 × 5 = - 10 and sum = - 9
The factors are - 10 and + 1
Use these factors to split the middle term
- 2x² - 10x + x + 5 = 0 ( factor the first/second and third/fourth terms )
- 2x(x + 5) + 1(x + 5) ( factor out (x + 5) )
(x + 5)(- 2x + 1) = 0
equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
- 2x + 1 = 0 ⇒ x = 
x-intercepts are x = - 5 and x = 
Answer:
the answer is DBC=90°
because the midpoint of the perimeter of quadrilateral is B
Answer:
zero
Step-by-step explanation:
Here, we want to get the sign of the expression
since a is zero, it multiplies any value in the brackets to be zero too
zero is neither positive nor negative
What this mean is that we can only explicitly classify the sign as zero
Answer:
(d) -11
Step-by-step explanation:
The sum of the acute angles of a right triangle is 90°. (That makes the sum of all angles be 180°, as it is for any triangle.)
65° +(36 +x)° = 90°
x = 90 -101 . . . . . . . . divide by °, subtract 101
x = -11
Answer:
I believe the answer you are looking for is "no"