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3 years ago

Can someone please help me

Mathematics

1 answer:

AysviL [449]3 years ago

5 0

Going from the top of the right side down it would be: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20

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Which number is a solution of the inequality 8 - 1/4 b > 27

Brrunno [24]

The inequality is 8-1/4x>27. The solution of the inequality is b<-76.

Given that,

The inequality is 8-1/4x>27

We must determine how to address the inequity.

Take,

8-1/4x>27

Multiply the inequality's two sides by its lowest common denominator,

4×8-4×1/4b>27×4

Reduce the expression to the lowers term,

4×8-b>4×27

Calculate the product or quotient,

32-b>4×27

Calculate the product or quotient,

32-b>108

Rearrange unknown terms to the left side of the equation,

-b>108-32

Calculate the sum or difference,

-b>76

Divide the inequality's two sides by the variable's coefficient,

b<-76

Therefore, the solution of the inequality is b<-76.

To learn more about inequality visit: brainly.com/question/28823603

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6 0

1 year ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .