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Gnesinka [82]
3 years ago
5

Help please! ty sm. image attached below

Mathematics
1 answer:
Bond [772]3 years ago
6 0

Answer:

its 5

Step-by-step explanation:

it's in between them

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Find the next number in the sequence: "-1, 1, 4, 8, 13, ..."
Afina-wow [57]

Answer:

19

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
P: 2,012
OleMash [197]

El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

<h3>¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?</h3>

En esta pregunta debemos encontrar el volumen <em>remanente</em> entre el espacio de una caja <em>cúbica</em> y una esfera introducida en el elemento anterior. El volumen <em>remanente</em> es igual a sustraer el volumen de la pelota del volumen de la caja.

Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:

Cubo

V = l³

V = (4 cm)³

V = 64 cm³

Esfera

V' = (4π / 3) · R³

V' = (4π / 3) · (2 cm)³

V' ≈ 33.5103 cm³

Segundo, determinamos la diferencia de volumen entre los dos elementos:

V'' = V - V'

V'' = 64 cm³ - 33.5103 cm³

V'' = 30.4897 cm³

El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

Para aprender más sobre volúmenes: brainly.com/question/23940577

#SPJ1

3 0
2 years ago
Bippity boppity pls help me find this functions property
Semmy [17]

Answer:

Period ⇒ 40

Amplitude ⇒ 12

Mid-line ⇒ 32

Step-by-step explanation:

The table is counting by 4's and the period is the amount of space between 2 peaks. In this scenario, we can find the peaks by looking for two of the same highest value (44). We can see that x=40 has a value of 44 while the other is actually not shown because it would be located at x=0. Therefore the period is 40

<u />

The amplitude can be found by using the following:

\frac{1}{2}|max - min|

Our maximum is 44 and our minimum is 20.

\frac{1}{2}|44 - 20|

\frac{1}{2}|24|

\frac{1}{2}(24)

The amplitude is 12

The amplitude is the distance from the peak to the mid-line. To find the mid-line, we can either subtract our amplitude from our maximum value (44) or add our amplitude to our minimum value (20)

44 - 12 = 32

20 + 12 = 32

Therefore our mid-line is y = 32

~Hope this helps!~

4 0
3 years ago
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natulia [17]
D- 2x-1
plug in a number for x and you'll see
6 0
3 years ago
7-^3<br> Simplify this expression. Use 7 as the base.
katen-ka-za [31]
Hopefully this photo helps

7 0
3 years ago
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