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stira [4]
3 years ago
9

HELP PLEASE QUICK! its 7-grade math

Mathematics
2 answers:
musickatia [10]3 years ago
5 0

answer:

1. yes

2. no

3. yes

4. no

step-by-step explanation:

  • for 1, yes because no matter what they are the signs are still the same
  • for 2, no because the signs have changed — 2/5 is positive now
  • yes because even though there is addition now, the signs are the same. when you use kcc (keep change change), the sign changes to +
  • no, because the coefficient for p is changed, which won't be true or give us the same result
algol133 years ago
3 0
Yes, no, Yes, no just a simple answer
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ivann1987 [24]

Answer:

Step-by-step explanation:

24√3

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3 years ago
Help please asap will mark brainliest !
Ber [7]

Answer:

b = 29

Step-by-step explanation:

C x D = A x B

15(11x - 91) = 7(2x + 10)

165x - 1365 = 14x + 70

add 1365 to both sides of the equation:

165x = 14x + 1435

subtract 14x from both sides:

151x = 1435

divide both sides by 151:

x = 9.5

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8 0
3 years ago
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

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Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
What is the value of x in the equation 5x+3=4x?
Volgvan

Answer:

x = -3

Step-by-step explanation:

5x + 3 = 4x,

x + 3 = 0,

x = -3

3 0
3 years ago
Read 2 more answers
Is this answer correct?
andre [41]
Thx no that answer is not correct
5 0
3 years ago
Read 2 more answers
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