Short Answer:Choice C [Third one down]
RemarkStart with the number so I can talk about the basic principle at work. The way to work it is to factor 162 into prime factors and hope there are at least 3 that are the same.
162 = 2 * 81
162 = 2 * 3 * 3 * 3 * 3
Now When you take the cube root of that, you get
![\sqrt[3]{2*2*2*2*3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2%2A2%2A2%2A2%2A3%7D%20)
Here's the rule for a cube root. For every 3 prime factors under the cuberoot sign, you take out one and throw the other two away. So for cube root of 81,
you would factor it as ∛(81) = ∛(3 * 3 * 3 * 3) = 3∛3.
So out of four 3s under the cube root sign, you have 1 outside the root sign and one inside the root sign. 2 of the four 3s have been thrown away.
Continuation.X firstYou want 2 xs outside the root sign
∛(x * x * x * x * x *x ) = (x * x) You have thrown away 2 xs for every x outside the cube root sign
C = 6 There are no left overs.
Y secondFor the ys, you need 1 outside and 2 inside the root sign. that's because you need 5 altogether.
∛(y * y * y * y * y) = y ∛y^2
Answer c = 6; d = 2
Choice C <<<<<< answer
This is exactly like normal subtraction, but with a fraction instead of an integer. Take one away from 360 and turn it into a fraction: 359 6/6 - 5/6. Now subtract the two fractions: 6/6 - 5/6 = 1/6. Add that to your number: 359 1/6.
0.4x30 +3= 15
700/15= 46...
46x30=1380
46x15=690
700-690=10
10/0.4=25
25+1380=1405(ans)
Answer: 17 miles per hour.
Step-by-step explanation:
1. To solve this problem you must apply the following formula:
=Δx/Δt
Where Δx is the position variation and Δt is the time variation.
2. Then, based on the graph shown attached, you have:
![S=\frac{20mi+20mi+30mi+15mi}{1h+1h+1h+2h}](https://tex.z-dn.net/?f=S%3D%5Cfrac%7B20mi%2B20mi%2B30mi%2B15mi%7D%7B1h%2B1h%2B1h%2B2h%7D)
3. Therefore, you have that the result is:
![S=17mi/h](https://tex.z-dn.net/?f=S%3D17mi%2Fh)
There are five whole numbers between 1 and 150 that have exactly 3 different factors. Whole numbers between 1 and 150 with exactly 3 different factors must be the square numbers whose square roots are prime.
To find the complete list begin counting...
skip 1, not prime;
2 is prime and 2 squared is 4;
3 is prime and 3 squared is 9;
skip 4 b/c it is not prime;
5 is prime and 5 squared is 25;
6 not prime;
7 prime and 7 squared is 49;
8 not prime;
10 not prime;
11 prime and squared is 121;
12 is not prime;
13 prime, but squared it is greater than 150.
The complete list is 4, 9, 25, 49, and 121. 4 has 1, 2, 4;
9 has 1, 3, 9;
25 has 1, 5, 25 ;
49 has 1, 7, 49 ;
121 has 1, 11, 121.
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