<span>1) Find an equation of the plane. The plane that passes through the point (2, 3, 4) and contains the line x = 4t, y = 2 + t, z = 3 − t 2) Find an equation of the plane. The plane that passes through (6, 0, −3) and contains the line x = 2 − 4t, y = 1 + 5t, z = 2 + 2t 3) Find an equation of the plane. The plane that passes through the point (1, −1, 1) and contains the line with symmetric equations x = 2y = 5z 4) Find the point at which the line intersects the given plane. x = 2 − t, y = 1 + t, z = 3t; x − y + 5z = 14 5) Find the point at which the line intersects the given plane. x = 2 + 2t, y = 3t, z = 4 − 2t; x + 2y − z + 2 = 0 6) Find the point at which the line intersects the given plane. x = y − 2 = 2z; 2x − y + 2z = 2</span>
YES IT IS!!
Work:
EQ: y= -x + 4
x= -6
y= 10
y= -x+4
1. 10= -(-6)+4
2. 10= +6+4
3. 10= 10
Answer:
B. hyperbola, 45°
Step-by-step explanation:
This is rotation in quadratic equations
Perform elimination of xy term
Ax² +B xy+Cy²+Dx+Ey+F=0
Rotation of axes of the coordinates through angle θ to satisfy
Cot 2θ =(A-C)/B
But B≠ 0 and A=C=0
Answer will be hyperbola, 45°
Answer:
1/3
Step-by-step explanation:
rise over run. Find two places that land on a line I picked (0,0) and (3,1) then count up one from the first point and over 3 for the second.
I should say 5 is the most clearest answer to me
