Since we are finding the inverse you switch the variable. So it is now x=7y+2 and now you solve for y. You would get x-2/7 = y for the inverse
We have that
<span>[6x+5]=1+2*(3x+2)
[6x+5]=1+2*3x+2 --------> is not correct ------->1+ 2*(3x+2)=1+2*3x+2*2
then
</span>[6x+5]=1+6x+4---------------> [6x+5]=[6x+5]
<span>this equation is an identity, all real numbers are solutions.</span>
If you are reflecting across the line y = x, then the x value becomes the y-vale and the y-value becomes the x-value. So the answer would be (6, -1) (Just trade places with x and y.)
Solve for c :
x⁴ + cx² + 100 = 0
cx² = -(x⁴ + 100)
c = - (x⁴ + 100)/x²
If x = 0, the right side is undefined and c would have no solution.
