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vivado [14]
3 years ago
13

-4 - 2 =2v-2+v+100\4

Mathematics
1 answer:
Kamila [148]3 years ago
4 0
X=-29/3 Original equation:<span>−4−2</span>=<span>2v−2+v+100/4 </span>
Simplify and combine like terms:<span><span><span>−4</span>+</span>−2</span>=<span><span><span><span><span>2v</span>+</span>−2</span>+v</span>+25</span><span><span>(<span><span>−4</span>+<span>−2</span></span>)</span>=<span><span>(<span><span>2v</span>+v</span>)</span>+<span>(<span><span>−2</span>+25</span>)
</span></span></span><span>−6</span>=<span><span>3v</span>+23</span><span><span>−6</span>=<span><span>3v</span>+<span>23
Flip Equation: </span></span></span><span><span>3v</span>+23</span>=<span>−<span>6
</span></span>Subtract 23 from each side:<span><span><span>3v</span>+23</span>−23</span>=<span><span>−6</span>−23</span>
<span><span>3v</span>=<span>−<span>29
</span></span></span>Divide each side by 3:<span><span><span>3v/</span>3</span>=<span><span>−29/</span>3</span></span><span>v=<span><span>−29/</span><span>3</span></span></span>
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Answer:

The probability is P(X = 5) = 142506*p^{5}*(1 - p)^{25}, in which p is the probability of a success on a single trial.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The trial is repeated 30 times:

This means that n = 30

Find the probability of 5 successes given the probability p of success on a single trial

This is P(X = 5). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{30,5}.p^{5}.(1 - p)^{25}

P(X = 5) = 142506*p^{5}*(1 - p)^{25}

The probability is P(X = 5) = 142506*p^{5}*(1 - p)^{25}, in which p is the probability of a success on a single trial.

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